The volume of oxygen necessary for the complete combustion of 20 L of propane is :
40 L
60 L
80 L
100 L
D.
100 L
Combustion of propane takes place as follows-
C3H8 + 5O2 → 3CO2 + 4H2O
1 L of propane required 5 L of oxygen for combustion.
20 L of propane required oxygen = 5 × 20 = 100 L
CH3COOH is weaker acid than H2SO4.It is due to:
more ionization
less ionization
covalent bond
electrovalent bond
A gaseous mixture contains 56 g of N2, 44 g of CO2 and 16 g of CH4. The total pressure of mixture is 720 mm of Hg. The partial pressure of methane is :
75 atm
160 atm
180 atm
215 atm
The solubility of Sb2S3 in water is 1.0 × 10-5 mol/L at 298K. What will be its solubility product?
108 × 10-25
1.0 × 10-25
144 × 10-25
126 × 10-24