Subject

Chemistry

Class

NEET Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

 Multiple Choice QuestionsMultiple Choice Questions

1.

The de-Broglie wavelenght of a particle with mass 1 kg and velocity 100 m/s is

  • 6.6 x 10-33 m

  • 6.6 x 10-36 m

  • 3.3 x 1033 m

  • 3.3 x 10-36 m


B.

6.6 x 10-36 m

The de broglie wavelength of a particle with mass 1 kg and velocity 100 m/s is 6.6 x 10-36 m.

λ = hmv = 6.6 × 10-341 × 100

  = 6.6 x 10-36 m


2.

BaO2 and ozone reacts to produce

  • Ba

  • Ba2O3

  • BaO

  • Ba(OH)3


C.

BaO

BaO2 and ozone reacts to produce BaO and oxygen.

BaO2 + O3  BaO + 2O2


3.

When copper reacts with hot and conc. H2SO4 gives

  • H2

  • N2

  • O2

  • SO2


D.

SO2

When copper reacts with hot and conc. H2SO4, SO2 is produced.

Cu + 2H2SO4 CuSO4 + SO2 + 4H2O


4.

What is X in the following nuclear reaction?

7N141H1 8O15 + X

  • 0n1

  • -1e0

  • +1e0

  • γ


D.

γ

X in the following reaction is gamma.

7N141H1  8O15γ


5.

The most stable compound is

  • LiF

  • LiCl

  • LiBr

  • LiI


A.

LiF

The electronegativity of halogen is as :

F > Cl >  Br > I

Among alkali metals the electropositive character increases as :

Li < Na < K < Rb < Cs

Hence, LiF is the most stable compound.


6.

A gas mixture contains O2 and N2 in the ratio of 1 : 4 by weight. The ratio of their number of molecules is

  • 1 : 8

  • 1 : 4

  • 3 : 16

  • 7 : 32


D.

7 : 32

The ratio of Oand N2 by weight is 1: 4

Therefore, the ratio of O2 and N2 by moles =

132 : 428 = 7 : 32

Hence, the ratio of the number of molecules is 7 : 32.


7.

The change in entropy for the fusion of 1 mole of ice is [mp of ice = 273 K, molar enthalpy of fusion for ice= 6.0 kJ mol-1]

  • 11.73 JK-1 mol-1

  • 18.84 JK-1 mol-1

  • 21.97 JK-1 mol-1

  • 24.47 JK-1 mol-1


C.

21.97 JK-1 mol-1

Entropy change of fusion

Sf = HfT

Hf = 60 x 103 JK mol-1; T = 273 K

Sf = 60 × 103273         = 21.97 JK-1 mol-1


8.

The volume of a gas measured at 27°C and 1 atm pressure is 10 L. To reduce the volume to 2 L at 1 atm pressure, the temperature required is

  • 60 K

  • 75 K

  • 150 K

  • 225 K


A.

60 K

Here, V1 = 10 L; V2 = 2 L

p1 = 1 atm; p2 = 1 atm

T1 = 300 K; T2 = x

p1V1T1 = p2V2T21 × 10300  = 1 × 2T2T2 = 300 × 210 = 60 K


9.

Heisenberg uncertainty principle can be explained as

  • x  P × h4π

  • x × P  h4π

  • x × P  hπ

  • P  πhx


B.

x × P  h4π

According to Heisenberg uncertainty principle, the product of uncertainty in momentum (P) and in position (x) remains constant. Therefore, it can be explained using the following formula 

x × P  h4π


10.

Neutron is discovered by

  • Chadwick

  • Rutherford

  • Yukawa

  • Dalton


A.

Chadwick

Neutrons are the particles in an atom that have a neutral charge. These particles were discovered by Chadwick.