﻿ In transforming 0.01 mole of PbS to PbSO4, the volume of 10 volu

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## NEET Chemistry Solved Question Paper 2008

#### Multiple Choice Questions

1.

Sodium nitrate on reduction with Zn in presence of NaOH solution produces NH3. Mass of sodium nitrate absorbing 1 mole of electron will be

• 7.750

• 10.625

• 8.000

• 9.875

# 2.In transforming 0.01 mole of PbS to PbSO4, the volume of '10 volume' H2O2 required will be11.2 mL 22.4 mL 33.6 mL 44.8 mL

D.

44.8 mL

From the equation given below,

PbS + 4H2O2 → PbSO4 + 4H2O

$\because$ 1 mole of PbS requires 4 moles of H2O2.

$\therefore$ 0.01 moles of PbS requires 0.04 mole of H2O2.

Now,

Weight of 0.04 mole H2O2 = 1.36 gm

And, 10 volume of H2O2 means,

1 mL of such solution of H2O2 on decomposition by heat produces 10 mL of oxygen at NTP.

H2O2 decomposes itself as,

2H2O2 → 2H2O + O2

Thus, 1 mL of 10 volume of H2O2 solution contains

$\frac{68}{22400}$ × 10 gm of H2O2 = 0.03035 gm H2O2

$\because$ 0.03035 gm of H2O2 is present in 1 mL of 10 volume of H2O2

$\therefore$ 1.36 gm of H2O2 present in $\frac{1}{0.03035}$ × 1.36 mL of 10 volume of H2O2

= 44.81 mL

3.

An unknown element forms an oxide.What will be the equivalent weight of the element if the oxygen content is 20% by weight?

• 16

• 32

• 8

• 64

4.

2 N HCl solution will have same molar concentration as a

• 4.0 N H2SO4

• 0.5 N H2SO4

• 1 N H2SO4

• 2 N H2SO4

5.

Addition of sodium acetate to 0.1 M acetic acid will cause

• increase in pH

• decrease in pH

• no change in pH

• change in pH that cannot be predicted

6.

The electronic configuration 1s2, 2s22p6, 3s23p63d9 represents a

• metal atom

• non metal atom

• non-metallic anion

• metallic cation

7.

Unusually high boiling point of water is result of

• intermolecular hydrogen bonding

• intramolecular hydrogen bonding

• both intra and inter molecular hydrogen bonding

• high specific heat

8.

In a given shell the order of screening effect is

• s > p > d > f

• s > p > f > d

• f > d > p > s

• s < p < d < f

9.

A catalyst is a substance which

• increases the equilibrium constant of the reaction

• increases equilibrium concentration of products

• does not alter the reaction mechanism

• changes the activation energy of the reaction

10.

Which of the following expressions gives the de-Broglie relationship?

• $\mathrm{p}=\frac{\mathrm{h}}{\mathrm{mv}}$

• $\mathrm{\lambda }=\frac{\mathrm{h}}{\mathrm{mv}}$

• $\mathrm{\lambda }=\frac{\mathrm{h}}{\mathrm{mp}}$

• $\mathrm{\lambda m}=\frac{\mathrm{v}}{\mathrm{p}}$