NEET Chemistry Solved Question Paper 2010

Heavy water is used as a moderator in nuclear reactors. Its boiling point is higher as compared to the ordinary water. Thus, it is more associated as compared to ordinary water. The dielectric constant is however higher for H₂O, thus, H₂O is a more effective solvent than heavy water (D₂O).

The order of size of given cations is 

Li⁺ < Na⁺ < Cs⁺

and the order of the size of given anions is 

A) When K_P > Q, the reaction goes in the forward direction, ie, the reaction is spontaneous.

B) Given ΔG^o < RT lnQ, thus, ΔG^o _{= + ve and hence, the reaction is non-spontaneous.}

C) At equilibrium, Kp = Q

Electrophiles are electron deficient species. Among the given H₃O⁺ has lone pair of electron for donation, thus, it is not electron deficient and hence, does not behave like an electrophile.

When the number of hybrid orbitals, H  is 4, the hybridization is sp³ hybridization


Thus, only in SF₄ the central atom does not have sp³ hybridisation.

W = p_ext. ΔV
For vaccum,

p_text = 0
therefore,
W = 0  ΔV = 0

With the increase in the number of electron in the same shell, the atomic radii decrease due to increase in effective nuclear charge. However, atomic radii increases, as the number of shells increases. Thus, on moving down a group atomic radii increases.

The electronic configuration of the given elements is

Mg₁₂ = [Ne] 3s²
Ca₂₀ = [Ar] 4s²
P₁₅ = [Ne]3s² 3p³
Cl₁₇ = [Ne] 3s² 3p⁵

In Mg, P and Cl, the number of electrons is increasing in the same shell thus, the order of their atomic radii is

Cl <P < Mg

In Ca, the electron is entering in the higher shell, thus, it has the highest atomic radii among the given. Thus, the order of radii is

Cl < P < Mg < Ca

Given,

Volume , V = 0.03 m³
Temperature, T = 129 + 273 = 402 K
mass of methane, w = 6.0 g
mol. Mass of methane, M = 12.01 + 4 x 1.01 = 16.05
From, ideal gas equation,

pV = nRT