CaC₂ and H₂O reacts to produce C₂H₂ (acetylene gas).

CaC₂(s) + 2H₂O(l)$\to$Ca(OH)₂(aq) + C₂H₂

In the reaction, two moles of C-H bonds and two moles of C-Cl bonds are broken. Hence, energy absorbed is

= 2 x 416 + 2 x 325

= 1482kJ

Electronegativity, ionisation energy and electron affinity of s-block elements in their respective period is low but the atomic radius of the s-block elements is larger in their respective period due to less effective nuclear charge.

IUPAC name of the above compound is 3-methylpent-3-en-2-ol

Lewis acid is any substance that can accept a pair of non- bonding electrons, such as the H⁺ ions. It is an electron pair acceptor.

Lewis base is any substance that can donate a pair of electrons.

OH^-, F^- and NH₃ are Lewis base because they can donate a lone pair of electrons while H⁺ is a Lewis acid because it can accept a lone pair ofelectrons.

Ammonia is dried over quick lime (CaO). It cannot be dried over conc. H₂SO₄, P₂O₅ and CaCl₂ because it reacts with these compounds.

B₃N₃H₆ (borazine) is known as inorganic benzene. Borazine is isoelectronic,i.e. same number of electrons and isosteric,i.e. same number of atoms with benzene.

-NH₂, -OH and -R (alkyl groups) all are o/p- directing and they activates the benzene ring -(X) halogens are howevero/p-directing but deactivate the benzene ring by withdrawing electrons fron the ring due to -I effect.

${\mathrm{\mu }}_{\mathrm{cal}}$= e x d = 1.6 x 10^-19 x 2.29 x 10^-10

= 3.664 x 10^-29 C-m

% ionic character =$\frac{{\mathrm{\mu }}_{\exp }}{{\mathrm{\mu }}_{\mathrm{cal}}}=\frac{6.226\mathrm{x}{10}^{-30}}{3.664\times {10}^{-29}}\times 100$

= 17%

If both nitrogen and sulphur are present in a organic compound, they will give red blood colour with Lassaigne test due to the formation of ferric thiocyanate.

Na + C + S + N$\stackrel{∆}{\to }$NaSCN (sodium thiocyanate)

Fe³⁺ + 3NaSCN$\to$Fe(SCN)₃ + 3Na⁺

ferric thiocyanate