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NEET Chemistry Solved Question Paper 2010

Multiple Choice Questions

CaO and NaCl have the same crystal structure and approximately the same ionic radii. If U is the lattice energy ofNaCI, the approximate lattice energy of CaO is

Lattic energy = $- \frac{q_{1} q_{2}}{r^{2}}$ where q₁ and q₂ are charges on ions and r is the distance between them. Since interionic distances in CaO and NaCl are similar, (larger cation has smaller anion and vice versa) therefore, r is almost the same. Therefore, lattice energy depends only on charge. Since the magnitude of charge on Na⁺ and Cl^-ions is unity and that on Ca²⁺ and O^2-ions is 2 each, therefore, the lattice energy of CaO is four times the lattice energy of NaCl, i.e..4U.

100 cm³ of a given sample of H₂O₂ gives 1000 cm³ of O₂ at S.T.P. The given sample is

10% H₂O₂
90% H₂O₂
10 volume H₂O₂
100 volume H₂O₂

10 volume H₂O₂

Hydrogen peroxide can easily break down, or decompose, into water and oxygen by breaking up into two very reactive parts- either 2OH or an H and HO_2.

$\underset{100 ml}{2 H_{2} O_{2}} \to 2 H_{2} O + \underset{1000 mL}{O_{2}}$

or 1ml of H₂O₂ will give 10 ml of O₂ at STP.

Beryllium and aluminium exhibit many properties which are similar. But the two elements differ in

maximum covalency in compounds
exhibiting amphoteric nature in their oxides
forming covalent halides
forming polymeric hydrides

maximum covalency in compounds

Be exhibits maximum covalency of four whereas Al shows maximum covalency of six.

Match List I with List II and select the correct answer using the codes given below the lists:

List I	List II
A. $(\frac{δG}{δP})_{T}$	1. $μ_{π}$
B. $(\frac{δG}{δT})_{P}$	2. T
C. $(\frac{δH}{δS})_{P}$	3. -S
D. $(\frac{δT}{δP})_{H}$	4. P
	5. V

A-5, B-1, C-2, D-4
A-5, B-3, C-2, D-4
A-3, B-5, C-2, D-1
A-5, B-3, C-2, D-1

A-5, B-3, C-2, D-1

From thermodynamics, dG = VdP-SdT

At constant T, dT = 0 so that $(\frac{δG}{δP})_{T} = V$

At constant P dP = 0 so that $(\frac{δG}{δT}) = - S$

Also $μ_{JT} = (\frac{δT}{δP})_{H}$

In the ground state of Cu²⁺the number of shells occupied, subshells occupied, filled orbitals and unpaired electrons respectively are

4, 8, 15 0
3, 6, 15, 1
3, 6, 14, 0
4, 7, 14, 2

3, 6, 14, 0

Cu⁺= 1s² 2s² 2p6 3s² 3p⁶ 3d⁶

So, Shells occupied =3, sub- shell occupied = 6, filled orbital = 14 and unpaired electron = 0

Equal weight of CO and CH₄ are mixed together in an empty container at 300 K. The fraction of total pressure exerted by CH₄ is.

$\frac{16}{17}$
$\frac{7}{11}$
$\frac{8}{9}$
$\frac{5}{16}$

$\frac{7}{11}$

Let tje weight of CO = weight of CH₄

$Moles of CO = \frac{a}{28}$

$Moles of {CH}_{4} = \frac{a}{16}$

Total moles = $\frac{a}{28} + \frac{a}{16}$

$x_{{CH}_{4}} = \frac{a}{\frac{16}{\frac{a}{28} + \frac{a}{16}}} = \frac{a}{16} \times \frac{28 \times 16}{44 a} = \frac{14}{22} = \frac{7}{11}$

fraction of pressure exerted by CH₄ = 7/11

Which of the following is correct?

Ionic radius is proportional to atomic number.
Ionic radius is inversely proportional to atomic mass.
Ionic radius is inversely proportional to effective nuclear charge.
All are correct.

Ionic radius is inversely proportional to effective nuclear charge.

$r_{ionic} \propto \frac{1}{Z_{eff}}$

What is the pH of0.01 M glycine solution? For glycine K_a1= 4.5x10^-3 and K_a2=1.7x10^-10 298 K.

3.0
10.0
7.06
8.2

7.06

Glycine H₃N⁺CH2COO^- is more acidic than basic. Instead of K_b value, the second given K_a value is corresponding to the K_b value ( K_a $\times$ K_b = 10^-14). Hence, overall ionization constant,

K= K_a1 $\times$ K_a2

= 4.5 $\times$ 10-3 $\times$ 1.7 $\times 10^{- 3} = 7.65 \times 10^{- 13}$

$H^{+} = \sqrt{KC} = \sqrt{7.65 \times 10^{- 13} \times 0.01} = \sqrt{0.765 \times 10^{- 14}} = 0.87 \times 10^{- 7} M$

pH =-log (0.87 $\times$ 10^-7) = 7.06

Two flasks X and Y have capacity 1L and 2L respectively and each of them contains 1 mole of a gas. The temperatures of the flasks are so adjusted that average speed of molecules in X is twice as those in Y. The pressure in flask X would be