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# NEET Chemistry Solved Question Paper 2013

#### Multiple Choice Questions

11.

The correct set of quantum numbers for the unpaired electron of a chlorine atom is :

• 2 , 0 , 0 , +$\frac{1}{2}$

• 2 , 1 , -1 , +$\frac{1}{2}$

• 3 , 1 , -1 , $±\frac{1}{2}$

• 3 , 0 , 0 , $±\frac{1}{2}$

C.

3 , 1 , -1 , $±\frac{1}{2}$

17Cl = 1s2 2s2 2p6 3s2 3p5

$\therefore$One unpaired electron is present in 3p orbital

 $⥮$ $⥮$ $↑$

3p

r = 3     m = -1

l = 1      s = $±\frac{1}{2}$

# 12.A 25 W bulb emits monochromatic yellow light of wavelength of 0.57 $\mathrm{\mu }$m. Calculate the rate of emission of quanta per second.7.169 x 1019 4.569 x 1019 8.579 x 1019 9.662 x 1019

A.

7.169 x 1019

25 watt = 25 Js-1

E = NHv = $\frac{\mathrm{NHc}}{\mathrm{\lambda }}$

25 =

N = 7.169  x 1019 quanta s-1

13.

When 2.495 g of CuSO· x H2O (molar mass 249.5) is heated, 0.05 mole of H2O is lost. Therefore , x is :

• one

• three

• five

• seven

C.

five

Number of moles of CuSO4 . xH2O = $\frac{2.495}{249.5}$ = 0.01 mole

$\therefore$ Moles of H2O = 0.01 x mole

= 0.05 mole

x = 5

14.

Each NH3 molecule has six other NH3 molecules as nearest neighbours in solid state ; $∆$H of sublimation of NH3 molecule at the m.p. is 30.8 kJ mol-1 and in the absence of H-bonding estimated Ml of sublimation is 14.4 kJ mol-1 .Hence , strength of H-bond in solid NH3 is :

• 5.47 kJ mol-1

• 10.93 kJ mol-1

• 16.40 kJ mol-1

• - 16.40 kJ mol-1

A.

5.47 kJ mol-1

Total strength of all H-bonds :

= 30.8- 14.4

= 16.4kJ mol-1

There are six nearest neighbours, but each hydrogen bond involves 2 molecules. Hence, effective neighbours = 3.

Hence , strength of H-bond ;

$\frac{16.4}{3}$ = 5.47 KJ mol-1.

15.

Which of the following compounds is the weakest Bronsted base ?

C.

Compounds and both have a stronger tendency to accept a proton and hence are stronger Bronsted bases than phenol (c) and alcohol (d). Since, phenol is more acitive than alcohol , therefore, phenol has the least tendency to accept a proton and hence it is the weakest Bronsted base.

16.

Which one ofthe following is not tetrahedral in shape ?

• SiCl4

• N${\mathrm{H}}_{4}^{+}$

• CH4

• SF4

D.

SF4

SF4 has trigonal bipyramid geometry since it has sp3d hybridisation.

17.

When 6 g of a monobasic acid is dissolved in 100 mL solution , it is l N. What is equivalent mass of the acid ?

• 20 g equiv-1

• 40 g equiv-1

• 60 g equiv-1

• 80 g equiv-1

C.

60 g equiv-1

From w = $\frac{\mathrm{NEV}}{1000}$

E =  =

= 60 g equiv-1

18.

N2O is isoelectronic to CO2 and ${\mathrm{N}}_{3}^{-}$. Which of the following is the structure of N2O ?

• N-O-N

• N-N-O

C.

N-N-O

N2O is isoelectronic with COand N3. Hence, its structure is linear i.e. , N=N ➔ 0.

19.

Calculate the radius of a water molecule assuming to be spherical (density= 1 g mL-1) :

• 1.925 10-8 cm

• 1.925x 10-9 cm

• 1.925 10-10 cm

• 1.925 10-11 cm

A.

1.925 10-8 cm

Mass of one molecule =  g

Volume of one molecule =

= 3.0 x 10-23

= 3.0 x 10-23

r3

r = = 1.925 x 10-8 cm

20.

Number of lone pair in XeOF4 is :

• zero

• one

• two

• three

B.

one

Number of lone pair in XeOF4 is one ,

XeOF4 (sp3d2 hybridisation)