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NEET Chemistry Solved Question Paper 2014

Multiple Choice Questions

A body of mass x kg is moving with a velocity of 100 ms^-1. Its de-Broglie wavelength is 6.62 x 10^-35 m. Hence, x is :

[h = 6.62 x 10^-34Js]

0.1 Kg
0.25 Kg
0.15 Kg
0.2 Kg

0.1 Kg

$λ$ = $\frac{h}{mv}$

$∴$ m = $\frac{6.62 \times 10^{- 34}}{6.62 \times 10^{- 35} \times 100}$

= 0.1 Kg

0.5 mole of each of H₂ , SO₂ and CH₄ are kept in a container. A hole was made in the container . After 3h , the order of partial pressures in the container will be :

pSO₂ > pH₂ > pCH₄
pSO₂ > PCH₄ > pH₂
pH₂ > pSO₂ > pCH₄
pH₂ > pCH₄ > pSO₂

pSO₂ > PCH₄ > pH₂

Rate of diffusion $\propto$ $\frac{1}{\sqrt{molecular mass}}$

$∴$ Order of diffusion H₂ > CH₄ > SO₂

and amount left is in the order :
SO₂ > CH₄ > H₂

Hence, order of partial pressure is
pSO₂ > pCH₄ > pH₂

The cooling in refrigerator is due to :

the reaction of the refrigerator gas
the expansion of ice
the expansion of the gas in the refrigerator
the work of the compressor

the expansion of the gas in the refrigerator

This is based on Joule-Thomson effect.

An evacuated glass vessel weighs 50 g when empty, 144.0 g when filled with a liquid of density 0.47 g mL^-¹and 50.5 g when filled with an ideal gas at 760 mm Hg and 300 K. The molar mass of the ideal gas is :

[R = 0.0821 L atm K^-1 mol^-1]

61.575
130.98
123.75
47.87

61.575

Weight of empty glass vessel = 50 g
Weight of glass vessel filled with liquid = 144.0 g

$∴$ Weight of liquid = 144- 50 = 94g
Density of liquid= 0.47 gmL^-1

$∴$ Volume of liquid = $\frac{94}{0.47}$ = 200mL = 0.2L

Mass of glass vessel filled with gas= 50.5 g

$∴$ Mass of gas (m) = 50.5- 50 = 0.5 g

By using ideal gas equation ,

pV = $\frac{m}{W}$ RT

where , p= 760 mm, Hg= 1atm ,
V = 0.2 L , T = 300K ,
and R = 0.0821 L atm K^-1 mol^-1

$∴$ Molar mass (M) = $\frac{mRT}{pV}$

= $\frac{0.5 \times 0.0821 \times 300}{1 \times 0.2}$

= 61.575g mol^-1

Pick out the incorrect statement from the following :

sp hybrid orbitals are equivalent and are at an angle of 180° with each other
sp² hybrid orbitals are equivalent and bond angle between any two of them is 120°
sp³d²hybrid orbitals are equivalent and are oriented towards corners of a regular octahedron
dsp² hybrid orbitals are equivalent with a bond angle of 90° between the two atoms

dsp² hybrid orbitals are equivalent with a bond angle of 90° between the two atoms

Angle between any two dsp² hybrid orbitals can be 90° or 180°

A precipitate of AgCl is formed when equal volumes of the following are mixed :

[K_sp for AgCl = 10^-10]

10^-4 M AgNO₃ and 10^-7 M HCl
10^-5 M AgNO₃ and 10^-6 M HCl
10^-5 M AgNO₃ and 10^-4 M HCl
10^-6 M AgNO₃ and 10^-6 M HCl

10^-5 M AgNO₃ and 10^-6 M HCl

For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product. A precipitate of AgCl is formed when equal volumes of 10^-5 M AgNO₃and 10^-5 M HCl are mixed, because ionic product will be 10^-9 which is greater than K_sp (10^-10).

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is :

188

Atomic mass of the metal = 32 x 2 = 64

Formula of metal nitrate= M(NO₃)₂

$∴$ Molecular mass = 64 + (14 + 3 x 16) x 2 = 188

In an exothermic equilibrium ,

A + 3B $⇌$ AB₃

all the reactants and products are in gaseous state. The formation of AB₃ is favoured at :

low temperature and low pressure
low temperature and high pressure
high temperature and high pressure
high temperature and low pressure

low temperature and high pressure

The given reaction is exothermic ( $Δ$ H < 0) and accompanied by decrease in the number of moles. Hence, it will be favoured by low temperature and high pressure.