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# NEET Chemistry Solved Question Paper 2017

#### Multiple Choice Questions

1.

As the temperature is raised from 20°C to 40C, the average kinetic energy of neon atoms changes by a factor:

• $\frac{313}{293}$

• $\sqrt{\left(\frac{313}{293}\right)}$

• $\frac{1}{2}$

• 2

A.

$\frac{313}{293}$

Avg. kinetic energy $\mathrm{\alpha }$T (kelvin)

2.

At relatively high pressure, vander Waal's equation reduces to:

• pV=RT

• pV=RT$-\frac{\mathrm{a}}{\mathrm{V}}$

• pV=RT$-\frac{\mathrm{a}}{{\mathrm{V}}^{2}}$

• pV=RT+pb

D.

pV=RT+pb

At high pressure, the pressure correction for 1 mole of gas is negligible $\frac{\mathrm{a}}{{\mathrm{V}}^{2}}=0$

However, the volume correction cannot be neglected. Hence, van der Waal's equation reduced to,

(p+0)(V-b)=RT                [For 1 mole]

pV-pb=RT

pV=RT+pb

3.

The first ionisation enthalpy of boron is less than beryllium because:

• Boron has high nuclear charge

• The size of boron atom is more than beryllium atom

• p-subshell of boron has only one electron

• The size cit boron atom is less than beryllium atom

C.

p-subshell of boron has only one electron

Beryllium has 2s2 outer shell configuration,
while boron has a 2s2 2pconfiguration.

4.

:

• CaO does not react to CO2  to give CaCO3

• backward reaction is very low

• CO2 formed escapes out

• None of the above

C.

CO2 formed escapes out

In the lime kiln the CO2 formed during decomposition of calcium carbonates escape out continuously. Hence the reaction is not a reversible one and proceeds towards completion.
On the other hand if the reaction takes places in a closed container where none of the reactant or product is allowed to escape then the reaction soon reaches the equilibrium state.

5.

When NaNO3 is heated in a closed vessel oxygen is liberated and NaNO3 is left behind,

At equilibrium:

• addition of NaNO2 favours reverse reaction

• addition of NaNO3 favours reverse reaction

• increasing temperature favours forward reaction

• decreasing temperature favours backward reaction

C.

increasing temperature favours forward reaction

6.

For an electron whose x-positional uncertainity is 1x 10-10 m, the uncertainity in the x-component of the velocity in ms-1 will be of the order of:

• 106

• 103

• 1012

• 1015

A.

106

7.

Which of the following is the correct increasing bond order for the given diatomic species?

• $\mathrm{NO}<{\mathrm{O}}_{2}^{-}<{\mathrm{C}}_{2}^{2-}<{\mathrm{He}}_{2}^{-}$

• ${\mathrm{C}}_{2}^{2-}<{\mathrm{He}}_{2}^{2+}<{\mathrm{O}}_{2}^{-}<\mathrm{NO}$

• ${\mathrm{He}}_{2}^{+}<{\mathrm{O}}_{2}^{-}<\mathrm{NO}<{\mathrm{C}}_{2}^{2-}$

• ${\mathrm{O}}_{2}^{-}<\mathrm{NO}<{\mathrm{C}}_{2}^{2-}<{\mathrm{He}}_{2}^{+}$

C.

${\mathrm{He}}_{2}^{+}<{\mathrm{O}}_{2}^{-}<\mathrm{NO}<{\mathrm{C}}_{2}^{2-}$

Bond order=$=\frac{{\mathrm{N}}_{\mathrm{b}}-{\mathrm{N}}_{\mathrm{a}}}{2}$

Thus, the correct order of bond order is,

${\mathrm{He}}_{2}^{+}<{\mathrm{O}}_{2}^{-}<\mathrm{NO}<{\mathrm{C}}_{2}^{2-}$

8.

Which of the following statement(s) is/are correct regarding shielding effect?

• The magnitude of screening effect do not depends upon the number of inner electrons

• The magnitude of effective nuclear charge decreases in a period.

• Greater the shielding effect, lower will be the atomic radii

• For a given 'orbit' the shielding effect of electron belonging to different subshell decrease in the order s > p > d >f

D.

For a given 'orbit' the shielding effect of electron belonging to different subshell decrease in the order s > p > d >f

Shielding effect of all the !inner electrons is not equal. It also depends upon the subshell in which electrons are present. For a given orbit, the shielding effect of electron belonging to different subshels decreases in the order.
s>p>d>f
The screening effect of d and I-orbitals is taken as almost constant.

9.

The dipole moment of HBr is 2.60 x 10-30 Cm and the interatomic spacing is 1.41 $\stackrel{\circ }{\mathrm{A}}$ .The percent ionic character of HBr is:

• 11.5%

• 10.1%

• 8.2%

• 4.1%

A.

11.5%

Theoretical value of dipole moment of a 100% ionic character

= e x d

=(1.60 x 10-19 C) (1.41 x 10-10 m)

=2.26 X 10-29 Cm

Observed value of dipole moment

=2.60 x 10-30 Cm

percent ionic character

10.

The wavelength of a spectral line emitted by hydrogen atom in the Lyman series is $\frac{16}{15\mathrm{R}}\mathrm{cm}$.
The value of n, will be

[R=Rydberg constant]

• 1

• 2

• 3

• 4

D.

4

For Lyman series,