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SSCCGL Quantitative Aptitude Solved Question Paper 2011

Multiple Choice Questions

111.

When 2³³ is divided by 10, the remainder will be

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112.

The value of $3 plus fraction numerator 1 over denominator 3 plus begin display style fraction numerator 1 over denominator 3 plus begin display style 1 third end style end fraction end style end fraction$ is

$40 over 11$
$43 over 11$
$46 over 11$
$41 over 11$

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113.

Find the unit digit in the product (4387)²⁴⁵ x (621)⁷²

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114.

If $square root of 2 space equals space 1.4142 comma$ find the value of $2 square root of 2 space plus space square root of 2 space plus space fraction numerator 1 over denominator 2 plus square root of 2 end fraction space plus space fraction numerator 1 over denominator square root of 2 minus 2 end fraction$

1.4144
2.8284
28.284
2.4142

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115.

If X * Y = X² + Y² - XY, then 11 * 13 is

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116.
If $square root of 1 plus straight x over 961 end root space equals space 32 over 31$ , then the value of x is

63

61

65

64

$square root of 1 plus straight x over 961 end root space equals space 32 over 31$
S.B.S.
$1 plus straight x over 961 space equals open parentheses 32 over 31 close parentheses squared space equals space 1024 over 961$
$rightwards double arrow space space space straight x over 961 space equals space 1024 over 961 minus 1 space equals space fraction numerator 1024 minus 961 over denominator 961 end fraction space equals space 63 over 961 rightwards double arrow space space space straight x space equals space 63$