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SSCCGL Quantitative Aptitude Solved Question Paper 2012

Multiple Choice Questions

121.

If $straight x space equals space 2 space plus space square root of 3 space comma space space space straight y space equals space 2 minus square root of 3 comma$ then the value of $fraction numerator straight x squared plus straight y squared over denominator straight x cubed space plus space straight y cubed end fraction$ is

$7 over 38$
$7 over 40$
$7 over 19$
$7 over 26$

40 Views

122.

If a² + b² + c² = 2 (a - b - c) - 3, then the value of 2a - 3b + 4c is

30 Views

123.

If $2 straight x space minus space fraction numerator 1 over denominator 2 straight x end fraction space equals space 6 comma$ then the value of $straight x squared space plus space fraction numerator 1 over denominator 16 straight x squared end fraction$ is

$19 over 2$
$17 over 2$
$18 over 3$
$15 over 2$

33 Views

124.

If $5 straight a space plus space fraction numerator 1 over denominator 3 straight a end fraction space equals space 5 comma$ then the value of $9 straight a squared space plus space fraction numerator 1 over denominator 25 straight a squared end fraction$ is

$34 over 5$
$39 over 5$
$42 over 5$
$52 over 5$

30 Views

125.
The area of the triangle formed by the lines 5x + 7y = 35, 4x + 3y = 12 and x-axis is

160/13 sq units

150/13 sq units

140/13 sq units

10 sq units

160/13 sq units

5x + 7y = 35 ...(i)
On x-axis, Y is 0
5x + 7 x 0 = 35
5x = 35
x = 7
∴ The required vertice on x-axis (7, 0)

Similarly,
4x + 3y = 12...(ii)
On x-axis, Y is 0
4x + 0 = 12
x = 3
∴ The required vertex on x-axis (3, 0)

Now,
Point of intersection is given by,
By Solving (i) and (ii), we get

Now, In ΔABC,

h = 80/13, Base (b) = (7 - 3) = 4
∴ Required area