﻿ SSC - CGL Quantitative Aptitude Solved Question Paper 2013 | Previous Year Papers | Zigya

## Subject

Quantitative Aptitude

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# SSCCGL Quantitative Aptitude Solved Question Paper 2013

#### Multiple Choice Questions

4.

Find the sum of: • n

• • (n + 1)

• B.   135 Views

9.

Find the value of: • 5

• • 6

• 7

C.

6 S.B.S.   Shortcut Method:
Choose two co-prime factors of 30. i.e .(6, 5) and the select the largest one. i.e. 6.
116 Views

1.

When 335 is added to 5A7, the result is 8B2. 8B2 is divisible by 3. What is the largest possible value of A?

• 8

• 2

• 1

• 4

D.

4

5  A  7
3  3  2
________
8   B    2

8B2 is exactly divisible by 3.
∴  8 + B + 2 = multiple of 3
∴   B = 2 or 5 or 8
∴     A + 1 + 3 = 8
∴     A = 4

490 Views

8.

If a clock strikes appropriate number of times at each hour, how many times will it strike a day?

• 300

• 156

• 68

• 78

B.

156

Clock will strike 1 time at 1, 2 times at 2, 3 times at 3, and so on up through 12 times at 12.
This makes 1+2+3+4+5+6+7+8+9+10+11+12=78 times every 12 hours.
i.e. it strikes (78 x 2)  = 156 times in 24 hours.

620 Views

7.

The unit digit in 3 x 38 x 537 x 1256 is

• 4

• 2

• 6

• 8

D.

8

Unit's digit in 3 x 38 x 537 x 1256 = Unit's digit in 3 x 8 x 7 x 6 = 4 x 2 = 8

255 Views

3.

Which one of the numbers is divisible by 25?

• 303310

• 373355

• 303375

• 22040

C.

303375

A number is divisible by 25 if it ends with 00, 25, 50, or 75. (i.e. last two digits divisible by 25)  i.e.   303375 is the right one.

175 Views

5.

In a class there are'z' students. Out of them 'x' are boys. What part of the class is composed of girls?

• • • • C. Let boys be x.
Girls  = z - x
Girls composition in a class = 226 Views

10.

The odd term in the sequence
0, 7, 26, 63, 124, 217 is

• 217

• 7

• 26

• 63

A.

217

The pattern is:
13 - 1 = 1 - 1 = 0
23 - 1 = 8 - 1 = 7
33 - 1 = 27 - 1 = 26
43 - 1 = 64 - 1 = 63
53 - 1 = 125 - 1 = 124
63 - 1 = 216 - 1 = 215
Hence, 217 is the wrong one.

167 Views

2.

The greatest 4-digit number exactly number by 10, 15, 20 is

• 9990

• 9960

• 9980

• 9995

B.

9960

LCM of 10, 15 and 20 = 60
Largest 4-digit number  = 9999 ∴   Required number = 9999 - 39 = 9960

164 Views

6.

If the students of 9th class are arranged in a row of 6, 8, 12 or 16, no student is left behind. Then the possible number of students in the class is

• 60

• 72

• 80

• 96

D.

96

Required number of students  = L.C.M. of 6, 8, 12 and 16 is 96.

322 Views