Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

110.

The marked price of a table is ₹ 12000. If it was sold for ₹10500 after allowing a certain discount, then the rate of discount is

  • 10%

  • 12.5%

  • 15%

  • 17.5%


B.

12.5%

Let the rate of discount be x%.
According to the question,
   rightwards double arrow space space space straight x over 100 space cross times space 12000 space equals space left parenthesis 12000 space minus space 10500 right parenthesis
rightwards double arrow space space straight x over 100 space cross times space 12000 space equals space 1500
rightwards double arrow space space space straight x space equals space fraction numerator 1500 space cross times space 100 over denominator 12000 end fraction
rightwards double arrow space space space straight x space equals space 12.5 percent sign

31 Views

104.

A rational number between 3/4 and 3/8 is

  • 7/3

  • 16/9

  • 9/16

  • 1/7


C.

9/16

Required number
         equals space 1 half open parentheses 3 over 4 space plus space 3 over 8 close parentheses
equals space 1 half open parentheses 9 over 8 close parentheses
equals space 9 over 16
               

39 Views

102.

A and B can complete a work in 3 days. They start together but, after 2 days, B left the work. If the work is completed after 2 more days, B alone could do the work in

  • 4 days

  • 6 days

  • 8 days

  • 10 days


B.

6 days

Work done by A and B in 2 days = 2 over 3
∴   Remaining work
            equals space 1 space minus space 2 over 3 space equals space 1 third
As, B completes the open parentheses 1 third close parentheses remaining work in 2 days.
∴   B alone can do it in 3 x 2 = 6 days.

30 Views

106.

The diameters of two circles are the side of a square and the diagonal of the square. The ratio of the areas of the smaller circle and the larger circle is

  • 1 : 4

  • square root of 2 space colon space square root of 3

  • 1 space colon space square root of 2

  • 1 : 2


D.

1 : 2

For first circle,
Diameter of a circle  = Side of a square
⟹       2r = a
⟹         r = a/2

For second circle,
Diameter of a circle = Diagonal of a square
rightwards double arrow space space 2 straight r space equals space square root of 2 straight a
rightwards double arrow space space straight r space equals space fraction numerator square root of 2 straight a over denominator 2 end fraction
∴   Required ratio of the areas of the smaller circle and the larger circle is:
  equals space πr subscript 1 squared over πr subscript 2 squared
equals space fraction numerator straight pi space cross times space open parentheses begin display style straight a over 2 end style close parentheses squared over denominator straight pi space cross times space open parentheses begin display style fraction numerator square root of 2 straight a over denominator 2 end fraction end style close parentheses squared end fraction space equals space 1 half space equals space 1 space colon space 2






34 Views

107.

The total surface area of a sphere is 8 straight pi square unit. The volume of the sphere is

  • 8 divided by 3 space straight pi cu unit.

  • 8 square root of 3 space straight pi space cu space unit

  • fraction numerator 8 square root of 3 over denominator 5 end fraction straight pi space cu space unit

  • fraction numerator 8 square root of 2 over denominator 3 end fraction straight pi space cu space unit


D.

fraction numerator 8 square root of 2 over denominator 3 end fraction straight pi space cu space unit

Total surface area of sphere equals space 8 straight pi
rightwards double arrow space space space 4 πr squared space equals space 8 straight pi
rightwards double arrow space space space space straight r space equals space square root of 2 space unit
∴  Volume of sphere:
              equals space 4 over 3 πr cubed space equals space 4 over 3 cross times space straight pi space cross times space left parenthesis square root of 2 right parenthesis cubed space equals space fraction numerator 8 square root of 2 over denominator 3 end fraction straight pi space cu space unit

                        

30 Views

105.

Product of two co-prime numbers is 117. Then their LCM is

  • 9

  • 13

  • 39

  • 117


D.

117

L.C.M. of two co-primes is equal to their product.

42 Views

103.

A does 20% less work than B. If A can complete a piece of work in 7 1 half straight h comma then B can do it in 

  • 4h

  • 6h

  • 8h

  • 10h


B.

6h

Ratio of times taken by A and B  = 100 : 80
Then, According to question,
       100 space colon space 80 space space space colon thin space colon space space 15 over 2 space colon space straight x
      rightwards double arrow space space 100 straight x space equals space 80 space cross times space 15 over 2
rightwards double arrow space space straight x space equals space space fraction numerator 40 space cross times space 15 over denominator 100 end fraction
rightwards double arrow space space straight x space equals space 6 space straight h

33 Views

108.

A conical flask is full of water. The flask has base radius r and height h. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is

  • straight h over 2 straight m squared

  • fraction numerator 2 straight h over denominator straight m end fraction

  • fraction numerator straight h over denominator 3 straight m squared end fraction

  • fraction numerator straight m over denominator 2 straight h end fraction


C.

fraction numerator straight h over denominator 3 straight m squared end fraction

Volume of conical flask = Volume of water
                                equals space 1 third πr squared straight h
Now, the water is poured into the cylindrical flask.
Therefore, According to the question,
                Volume of cylinder = Volume of water
            rightwards double arrow space space straight pi left parenthesis mr right parenthesis squared space cross times space Height space equals space 1 third πr squared straight h
therefore space space space space space Height space space equals space fraction numerator straight h over denominator 3 straight m squared end fraction


33 Views

109.

A dozen pairs of socks quoted at ₹ 180 are available at discount of 20%. How many pairs of socks can be bought for ₹ 48?

  • 4 pairs

  • 2 pairs

  • 5 pairs

  • 3 pairs


A.

4 pairs

Cost of a dozen pair of socks after discount:
             equals space 180 space cross times space fraction numerator left parenthesis 100 minus 20 right parenthesis over denominator 100 end fraction
equals space 180 space cross times space 80 over 100 space equals space space ₹ space 144
∴    Cost of 1 pair of socks
                      equals space 144 over 12 space equals space ₹ space 12
Thus, with ₹ 48 total pairs of socks can be bought:
               equals space 48 over 12 space equals space 4 space pairs

29 Views

101.

A and B together can complete a piece of work in 12 days. B and C can do it in 20 days and C and A can do it in 15 days. A, B and C together it in

  • 6 days

  • 8 days

  • 10 days

  • 12 days


C.

10 days

Shortcut Method:
Let A, B and C together can complete a piece of work in x days.
Now, 
rightwards double arrow space space space space space straight x over 12 space plus space straight x over 20 space plus space straight x over 15 space equals space 2
rightwards double arrow space space space space space fraction numerator 5 straight x space plus space 3 straight x space plus space 4 straight x over denominator 60 end fraction space equals space 2
rightwards double arrow space space space space space space space fraction numerator 12 straight x over denominator 60 end fraction space equals space 2
rightwards double arrow space space space space space space space straight x space equals space 10 space days

55 Views