Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

60.

Possible measures of three angles of a triangle are

  • 33°, 42°, 115°

  • 40°, 70°, 80°

  • 30°, 60°, 100°

  • 50°, 60°, 70°


D.

50°, 60°, 70°

As the sum of all angles of triangles is 180°.
 i.e., angle straight A plus angle straight B plus angle straight C space equals space 180 degree
So, option (4) is the correct answer.

168 Views

51.

A and B can together do a piece of work in 6 days and A alone can do it in 9 days. The number of days B will take to do it alone is

  • 18 days

  • 24 days

  • 9 days

  • 12 days


A.

18 days

A and B together takes  = 6 days
and A together takes = 9 days
So,   B alone would take = fraction numerator 6 cross times 9 over denominator 9 minus 6 end fraction space equals fraction numerator begin display style space 54 end style over denominator 3 end fraction days space equals space 18 space days

249 Views

56.

There are 1400 students in a school, 25% of those wear spectacles 2 over 7 of those wearing spectacles are boys. How many girls in the school wear spectacles?

  • 250

  • 100

  • 200

  • 300


A.

250

 Total number of students  = 1400
  Number of students who wear spectacles
                            equals space 1400 space cross times 25 over 100 equals space space 350
therefore Number of boys who wear spectacles
                                    equals space 350 space cross times 2 over 7 space equals space 100
  Number of girls who wear spectacles  = 350 - 100 = 250

220 Views

52.

The length of the two parallel sides of a trapezium are 16m and 20 m respectively. If its height is 10 m, its area in square metres is:

  • 360

  • 260

  • 240

  • 180


D.

180

Area of trapezium = 1 half left parenthesis sum space of space parallel space sides right parenthesis space cross times space distance space between space them
                      equals space 1 half left parenthesis 16 plus 20 right parenthesis cross times 10
equals space 1 half cross times 36 cross times 10
equals space 180 space straight m squared

271 Views

58.

If ab = 21 and fraction numerator left parenthesis straight a plus straight b right parenthesis squared over denominator left parenthesis straight a minus straight b right parenthesis end fraction space equals space 25 over 4 then value of straight a squared plus straight b squared plus 3 ab is

  • 115

  • 121

  • 125

  • 127


B.

121

             ab = 21                         ...(i)
          fraction numerator left parenthesis straight a plus straight b right parenthesis squared over denominator left parenthesis straight a minus straight b right parenthesis squared end fraction space equals space 25 over 4
rightwards double arrow space space open parentheses fraction numerator straight a plus straight b over denominator straight a minus straight b end fraction close parentheses squared space equals space 25 over 4
rightwards double arrow space space space space space space fraction numerator straight a plus straight b over denominator straight a minus straight b end fraction space equals space 5 over 2
rightwards double arrow space space space space space 2 straight a plus 2 straight b space equals space 5 straight a minus 5 straight b
rightwards double arrow            3a = 7b
rightwards double arrow             straight a space equals space fraction numerator 7 straight b over denominator 3 end fraction                  ...(ii)
From equation (i),
                   fraction numerator 7 straight b cross times straight b over denominator 3 end fraction equals 21
                straight b squared space equals space 9
From equation (ii),
 straight a space equals space fraction numerator 7 cross times 3 over denominator 3 end fraction space equals space 7
therefore      straight a squared plus straight b squared plus 3 ab space equals space left parenthesis 7 right parenthesis squared plus left parenthesis 3 right parenthesis squared plus 3 cross times 7 cross times 3
                            =  49 +  9 + 63
                            = 121                  



155 Views

55.

A dealer sold an article at 6% loss. Had he sold it for Rs 64 more, he would have made a profit of 10%. Then the cost of the article is

  • Rs.400

  • Rs.200

  • Rs.164

  • Rs.464


A.

Rs.400

By shortcut method:
Cost of the article  = fraction numerator 64 over denominator 6 plus 10 end fraction cross times 100
                          equals 64 over 16 cross times 100
equals space 400
Therefore,  the cost of an article would be Rs. 400

459 Views

53.

A discount series of 15%, 20% and 25% is equal to the single discount of

  • 48%

  • 49%

  • 50%

  • 51%


B.

49%

For finding out the single discount apply the formula:
straight A plus straight B minus AB over 100
i.e. Single discount of 15% and 20% = 15 plus 20 minus fraction numerator 15 cross times 20 over denominator 100 end fraction = 32%
  Single discount of 25% and 32% = 25 plus 32 minus fraction numerator 25 cross times 32 over denominator 100 end fraction = 49%

 

235 Views

57.

A man can row upstream at 12 km/hr and downstream at 18 km/hr. The man's rowing speed in still water is

  • 15 km/hr

  • 5 km/hr

  • 3 km/hr

  • 10 km/hr


A.

15 km/hr

The speed of boat in still water = 1 half left parenthesis 12 plus 18 right parenthesis space km divided by hr space equals space 30 over 2 space equals space 15 space km divided by hr

394 Views

59.

The value of left parenthesis straight d to the power of straight s plus straight t end exponent space divided by space straight d to the power of straight s right parenthesis space divided by space straight d to the power of straight t would be

  • straight d to the power of 2 left parenthesis straight s plus straight t right parenthesis end exponent
  • 1

  • 0

  • straight d to the power of straight s plus straight t end exponent

B.

1

left parenthesis straight d to the power of straight s plus straight t end exponent space divided by space straight d to the power of straight s right parenthesis space divided by space straight d to the power of straight t space equals space open parentheses straight d to the power of straight s plus straight t end exponent over straight d to the power of straight s close parentheses space divided by space space straight d to the power of straight t
                        equals space left parenthesis straight d to the power of straight s plus straight t minus straight s end exponent right parenthesis divided by straight d to the power of straight t space equals space straight d to the power of straight t over straight d to the power of straight t space equals space 1
136 Views

54.

Rs.490 is divided among A, B and C such that A's share is half that of B's and thrice that of C's. What is C's share?

  • Rs 49

  • Rs 147

  • Rs 294

  • Rs 245


A.

Rs 49

Let A's share  = x
      B's share = 2x
      C's share = straight x over 3
According to the question,
                straight x plus 2 straight x plus straight x over 3 space equals space 490
                  fraction numerator 3 straight x plus 6 straight x plus straight x over denominator 3 end fraction space equals space 490
                       10 straight x space equals space 490 space cross times space 3
space space straight x space equals space 147
therefore C's share  = 147 over 3 equals space space Rs space 49.

499 Views