Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

59.

If a = 2,  b = -3 then the value of 27 straight a cubed minus 54 straight a squared straight b space plus space 36 ab squared minus 8 straight b cubed is

  • 1562

  • 1616

  • 1676

  • 1728


D.

1728

27 straight a cubed minus 54 straight a squared straight b plus 36 ab squared minus 8 straight b cubed
rightwards double arrow space space space space left parenthesis 3 straight a right parenthesis cubed minus 3 cross times left parenthesis 3 straight a right parenthesis squared straight b plus 3 cross times 3 straight a left parenthesis 2 straight b right parenthesis squared minus left parenthesis 2 straight b right parenthesis cubed
rightwards double arrow space space space left parenthesis 3 straight a minus 2 straight b right parenthesis cubed
rightwards double arrow space space space left parenthesis 3 space straight x space 2 space plus space 2 space cross times 3 right parenthesis cubed space space space space space space space space space space space space space space space space space space left parenthesis Given comma space straight a space equals space 2 comma space space straight b space equals space minus 3 right parenthesis
rightwards double arrow space space space space left parenthesis 6 space plus space 6 right parenthesis cubed space equals space left parenthesis 12 right parenthesis cubed space equals space 1728
95 Views

52.

A can do a piece of work in 18 days. He worked at it for 12 days and B finished the remaining work in 8 days. B alone can do the whole work in

  • 16 days

  • 24 days

  • 28 days

  • 29 days


B.

24 days

A's 1 day's work = 1 over 18
A's 12 days' work = 12 over 18 equals space 2 over 3
   Remaining work = 1 minus 2 over 3 space equals space 1 third
B finishes 1 third of work in 8 days.
therefore B can complete the whole work  = 8 x 3 = 24 days

150 Views

51.

The sum of three consecutive natural numbers each divisible by 5, is 225. The largest among them is

  • 85

  • 75

  • 70

  • 80


D.

80

Let the three consecutive natural numbers each divisible by 5 be x, (x+5) and (x+10) respectively.
 According to the question,
    x +  x + 5 + x + 10 = 225
                 3x + 15 = 225
                        3x = 210
                          x = 70
therefore The largest number = x + 10 = 70 + 10 = 80

370 Views

60.

Possible length of the three sides of a triangle are

  • 2 cm, 3 cm, 6 cm

  • 3 cm,  4cm, 5cm

  • 2.5 cm, 3.5 cm, 6cm

  • 4cm, 4cm, 9cm


B.

3 cm,  4cm, 5cm

By option (2),
52 = 32 + 42
25 = 9 + 16
25 = 25

151 Views

55.

An article was sold at ₹ 950/- allowing 5% discount on the marked price. The marked price of the article is:

  • ₹ 960

  • ₹ 1000

  • ₹ 955

  • ₹ 945


B.

₹ 1000

Let the marked price of the article  = ₹ x
According to the question,
              straight x space cross times space 95 over 100 space equals space 950
                    straight x space equals space ₹ space 1000     

147 Views

53.

The list price of an article is ₹ 900/- It is available at two successive discounts of 20% and 10%. The selling price of the article is

  • ₹ 640

  • ₹ 648

  • ₹ 540

  • ₹ 548


B.

₹ 648

Selling price of the article = 900 space cross times space 80 over 100 space cross times space 90 over 100
                                      = ₹ 648

142 Views

57.

The time taken by a train 160 m long, running at 72 km/hr, in crossing an electric pole is

  • 8 sec

  • 9 sec

  • 6 sec

  • 4 sec


A.

8 sec

Required time = fraction numerator 160 space cross times space 18 over denominator 72 space cross times space 5 end fraction equals space space 8 space sec

222 Views

54.

A man spends a part of his monthly income and saves the rest. The ratio of his expenditure to the saving is 61 : 6. If his monthly income is ₹ 8,710/-. the amount of his monthly savings is

  • ₹ 870

  • ₹ 690 

  • ₹ 980

  • ₹ 780


D.

₹ 780

Amount of monthly savings  = 8710 space cross times space 6 over 67
                                        = ₹ 648

191 Views

58.

If straight x plus fraction numerator 1 over denominator 9 straight x end fraction space equals space 4 comma then 9 straight x squared plus fraction numerator 1 over denominator 9 straight x squared end fraction is

  • 140

  • 142

  • 144

  • 146


B.

142

straight x plus fraction numerator 1 over denominator 9 straight x end fraction space equals space 4
rightwards double arrow space space 3 straight x plus fraction numerator 3 over denominator 9 straight x end fraction space equals space 4 space cross times space 3
rightwards double arrow space 3 straight x space plus space fraction numerator 1 over denominator 3 straight x end fraction space equals space 12
             If open square brackets because space space straight x space plus space 1 over straight x space space equals space straight a comma space space space then space straight x squared plus 1 over straight x squared space equals space straight a squared minus 2 close square brackets
  rightwards double arrow space space 3 straight x squared plus fraction numerator 1 over denominator 3 straight x squared end fraction space equals space 144 minus 2
rightwards double arrow space space 3 straight x squared plus fraction numerator 1 over denominator 3 straight x squared end fraction space equals space 142
117 Views

56.

A person loses 75% of his money in the first bet, 75% of the remaining in the second and 75% of the remaining in the third bet and returns home with Rs. 2 only. His initial money was

  • ₹ 64

  • ₹ 128

  • ₹ 256

  • ₹ 512


B.

₹ 128

Let the initial money  = ₹ x 
According to the question
 straight x space cross times space fraction numerator left parenthesis 100 minus 75 right parenthesis over denominator 100 end fraction cross times fraction numerator left parenthesis 100 minus 75 right parenthesis over denominator 100 end fraction cross times fraction numerator left parenthesis 100 minus 75 right parenthesis over denominator 100 end fraction space equals space 2
                rightwards double arrow  straight x cross times 25 over 100 cross times 25 over 100 cross times 25 over 100 equals space 2
                 rightwards double arrow space space straight x space cross times space 1 fourth cross times 1 fourth cross times 1 fourth space equals space 2
rightwards double arrow space space straight x space equals space ₹ space 128

313 Views