Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

53.

The sum of three numbers is 540. The ratio of second to third is 9 : 13 and that of first to third is 2 : 7. The third number is

  • 273

  • 280

  • 250

  • 286


A.

273

B : C = 9 : 13  ...(i)
A : C = 2 : 7 
or 
C : A  = 7 :  2 ...(ii)
From (i) and (ii)
B : C : A = 9 x 7 : 13 x 7 : 13 x 2 = 63 : 91 : 26
Therefore,
Third number
straight C space equals space fraction numerator 91 over denominator left parenthesis 63 plus 91 plus 26 right parenthesis end fraction cross times 540
straight C space equals space 91 over 180 cross times space 540 space
straight C space equals space 273

84 Views

54.

An article is sold at a certain price. If it is sold at half of the previous selling price, then there is a loss of 25 1 half percent sign. The profit after selling the article at the previous selling price is:

  • 51%

  • 49%

  • 12 3 over 4 percent sign
  • 24 1 half percent sign

B.

49%

Let cost price be Rs. 100/-
and selling be Rs. x /-
According to the question,
  rightwards double arrow space space open parentheses fraction numerator 100 space minus space begin display style straight x over 2 end style over denominator 100 end fraction space cross times space 100 close parentheses space equals space 51 over 2
rightwards double arrow space space 200 space minus space straight x space equals space 51
rightwards double arrow space space space straight x space equals space 200 space minus space 51 space equals space ₹ space 149 divided by negative
∴  Gain percentage
     equals space open parentheses fraction numerator 149 minus 41 over denominator 100 end fraction space cross times space 100 close parentheses space equals space 49 percent sign





122 Views

51.

15 men can finish a piece of work in 40 days. The days after which 5 men should leave the work so that the work is finished in 45 days altogether is

  • 10

  • 20

  • 30

  • 35


C.

30

Let the required number of days be x.
According to the question,
M1W1 = M2W2
15 x 40 = 5 x (x) + 10 x (45)
600 = 5x + 450
5x = 150,   x = 30 

94 Views

52.

Cost price of an article is ₹ 200/-. If 20% profit is made after giving 20% discount on marked price, the marked price is

  • ₹ 300/-
  • ₹ 320/-

  • ₹ 420/-

  • ₹ 450/-


A.

₹ 300/-

Shortcut Method:
Marked space price space equals space Cost space price space open parentheses fraction numerator 100 space plus space Gain percent sign over denominator 100 space minus Discount percent sign right parenthesis end fraction close parentheses
                equals space 200 space cross times space 120 over 80 space equals space ₹ space 300 divided by negative

47 Views

59.

If a + b = 3,  then the value of a3 + b3 + 9ab is

  • 27

  • 9

  • 16

  • 81


A.

27

  a + b = 3
On cubing both sides,
(a + b)3 = (3)3
a3 + b3 + 3ab(a + b) = 27
a3 + b3 + 3ab x 3 = 27
∴  a3 + b3 + 9ab = 7

91 Views

55.

If A's salary is 30% more than that of B, then how much percent is B's salary less than that of A?

  • 13.01%

  • 13.07%

  • 23.07%

  • 23.01%


C.

23.07%

Required space percentage space equals space fraction numerator 30 over denominator left parenthesis 100 plus 30 right parenthesis end fraction space cross times space 100
rightwards double arrow space space space 30 over 130 space cross times space 100 space equals space 23.07 percent sign
126 Views

57.

The rate of simple interest for which ₹ 6,000/- will amount to ₹ 6,900/- in 3 years is

  • 5%

  • 7%

  • 2%

  • 4%


A.

5%

₹ (6,900 - 6,000) = 900 for 3 years is the S.I.
⟹  100 SI = PRT
⟹  100 X 900 = 6000 x R x 3
⟹  R = 5% p.a.
85 Views

60.

In a ΔABC,  D and E are points on AC and BC respectively, AB and DE are perpendicular to BC. If AB = 9cm, DE = 3 cm and AC  = 24 cm, then AD is

  • 32 cm

  • 16 cm

  • 8 cm

  • 4 cm


B.

16 cm

In a ΔABC,  D and E are points on AC and BC respective
Let AD = x cm
As ΔABC ~ ΔDEC
    rightwards double arrow space space space CD over AC space equals space DE over AB
rightwards double arrow space space space space fraction numerator 24 minus straight x over denominator 24 end fraction space equals space 3 over 9
rightwards double arrow space space space space 24 space minus straight x space equals space 8
therefore space space space straight x space equals space 16 space cm
105 Views

58.

If (a + b)2 = 100 and (a - b) = 4, then ab equals to

  • 116

  • 84

  • 21

  • 53


C.

21

(a + b)2 = 100
∴  a + b = 10                   ...(i)
    a - b = 4                      ...(ii)
On solving equations (i) and (ii),
           2a = 14  ⟹ a = 7,   b = 3
∴  ab = 7 x 3 = 21

50 Views

56.

A man travels for 14 hours 40 min. He covers half of the journey by train at the rate of 60 km/hr and rest half by road at the rate of 50 km/hr. The distance travelled by him is

  • 720 km

  • 800 km

  • 960 km

  • 1000 km


B.

800 km

Let total distance  = x km
According to the question,
Time space space equals space fraction numerator Distance space over denominator Speed end fraction
rightwards double arrow space space space 14 2 over 3 space equals space fraction numerator begin display style straight x over 2 end style over denominator 60 end fraction space plus space fraction numerator begin display style straight x over 2 end style over denominator 50 end fraction
rightwards double arrow space space space 44 over 3 space equals space straight x over 120 space plus space straight x over 100
rightwards double arrow space space space 44 over 3 space equals space fraction numerator 100 straight x space plus space 120 straight x over denominator 12000 end fraction
rightwards double arrow space space 44 space cross times space 4000 space equals space 220 straight x
rightwards double arrow space space space space straight x space equals space fraction numerator 44 space cross times space 4000 over denominator 220 end fraction comma space space space straight x space equals space 800 space km


173 Views