Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

52.

A shopkeeper gives two successive discounts of 7% each on marked price of ₹ 20,000/- of an article. The selling price of the article is

  • ₹ 12,798
  • ₹ 19,278

  • ₹ 18,927

  • ₹ 17,298


D.

₹ 17,298

Required selling price:
            20 comma 000 space cross times space 93 over 100 space cross times space space 93 over 100 space equals space ₹ space 17 comma 298 divided by negative

54 Views

59.

If x + y = 1 + xy, then x3 + y3 - x3y3 is equal to

  • 0

  • 1

  • -1

  • 2


B.

1

Put the value of x and y = 1
as it satisfies the equation
 x + y = 1 + xy
1 + 1 = 1+ 1.1
 2 = 2
∴  x3 + y3 - x3y3 = (1)3 + (1)3 - (1)3(1)3 = 2 - 1 = 1

69 Views

51.

If 35 men finish a piece of work in 8 days, then the number of men who can do the same work in 10 days is

  • 38

  • 28

  • 19

  • 17


B.

28

M1D1 = M2D2
35 x 8 = M2 x 10
M2 = 28 

97 Views

55.

In 2001, the price of a building was 80% of its original price. In 2002, the price was 60% of its original price. By what percent did the price decrease?

  • 15%

  • 20%

  • 25%

  • 30%


C.

25%

Let the original price be ₹ x
Price of building in 2001:
straight x space cross times space 80 over 100 space equals space 4 over 5 straight x
Price of building in 2002:
straight x space cross times space 60 over 100 space equals space 3 over 5 straight x
∴  Required percentage
                  equals space fraction numerator begin display style 4 over 5 end style straight x minus begin display style 3 over 5 end style straight x over denominator begin display style 4 over 5 end style straight x end fraction space cross times space 100
                  equals space 1 fourth space cross times space 100 space equals space 25 percent sign

75 Views

57.

If straight a over straight b space plus space straight b over straight a space equals space 1 comma then the value of a3 + b3 - 2 is

  • 0

  • -2

  • -1

  • 2


B.

-2

rightwards double arrow space space space straight a over straight b plus straight b over straight a space equals space 1
rightwards double arrow space space fraction numerator straight a squared plus straight b squared over denominator ab end fraction space equals space 1
rightwards double arrow space space space straight a squared space plus space straight b squared space minus ab space equals space 0
As,
 a3 + b3 = (a +b) (a2 + b2 - ab)
 a3 + b3 = (a + b) x 0
 a3 + b3 = 0
∴    a3 + b- 2 = 0 - 2 = -2 

55 Views

53.

The present ages of A and B are in the ratio 3 : 4. Ten years ago, this ratio was 4 : 7. The present age of A and B are respectively:

  • 18 years, 24 years

  • 21 years, 28 years

  • 24 years, 32 years

  • 27 years, 36 years


A.

18 years, 24 years

Let present age of A = 3x
And present age of B = 4x
According to the question,
   rightwards double arrow space space space fraction numerator 3 straight x minus 10 over denominator 4 straight x minus 10 end fraction space equals space 4 over 7
   rightwards double arrow space space 21 straight x space minus space 70 space equals space 16 straight x space minus space 40
rightwards double arrow space space space 5 straight x space equals space 30
rightwards double arrow space space space straight x space equals space 6 space years
∴ Present age of A = 3x = 3 x 6 = 18 years
  Present age of B = 4x = 4 x 6 = 24 years

78 Views

56.

Sound travels 330 m in a second. When the sound follows the flash of lightning after 10 sec, the thunder cloud will be at a distance of

  • 1300 m

  • 2000 m

  • 3650 m

  • 3300 m


D.

3300 m

Speed space of space sound space equals space Distance over Time space equals space 330 over 1 space equals space 330 space straight m divided by sec
Time = 10 sec
Distance  = Speed x Time
              = 330 x 10 = 3300 m
80 Views

54.

Sapna purchased a cycle for ₹ 1,000/- and sold it for ₹ 1,200/-. Her gain in percentage is

  • 20%

  • 10%

  • 12%

  • 40%


A.

20%

Gain = 1200 - 1000 = 200
therefore space space Required space gain space percentage space equals space 200 over 1000 space cross times space 100 space equals space 20 percent sign

48 Views

58.

The amount to be paid, when principal  = ₹ 2,000/-, Rate of simple interest (R) = 5%, T = 2 years, is

  • ₹ 3,200/-
  • ₹ 2,400/-
  • ₹ 2,200/-
  • ₹ 3,400/-

C.

₹ 2,200/-

100 S.I. = PRT
100 x S.I.  = ₹ 2,000 x 5 x 2
S.I. = ₹ 200/-
Required amount = Principal + Interest
                         = 2000 + 200 = ₹ 2200/-

56 Views

60.

The perimeter of two similar triangles ΔABC and ΔPQR are 60 cm and 36 cm respectively. If PQ = 18 cm, then AB is

  • 20 cm

  • 24 cm

  • 36 cm

  • 30 cm 


D.

30 cm 

Δ ABC ~ Δ PQR

fraction numerator Perimeter space of space increment ABC over denominator Perimeter space of space increment PQR end fraction space equals AB over PQ
rightwards double arrow space space 60 over 36 space equals space AB over 18
therefore space space AB space equals space 30 space cm
114 Views