Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

51.

A can do a piece of work in 9 days while B can do it in 12 days. A and B together can do the work in 

  • 5 1 over 7 space days
  • 5 2 over 7 space days
  • 6 1 over 7 space days
  • 6 2 over 7 space days

A.

5 1 over 7 space days

A and B together can do a piece of work :
  rightwards double arrow space open parentheses fraction numerator straight A space cross times space straight B over denominator straight A plus space straight B end fraction close parentheses space equals space open parentheses fraction numerator 9 space cross times space 12 over denominator 21 end fraction close parentheses space equals space 36 over 7 space equals space 5 1 over 7 space days

 

81 Views

52.

A retailer gets a discount of 40% on the marked price of an article. The retailer sells it at the printed price. His gain percent is

  • 40%

  • 55%

  • 66 2 over 3 percent sign
  • 75%


C.

66 2 over 3 percent sign

Let the marked price of article be Rs. 100
∴ Cost price of an article for the retailer
           equals space 100 space cross times space 60 over 100 space equals space Rs. space 60
Selling price of article would be the (marked price) Rs. 100 
∴  Required gain percentage
   equals space fraction numerator 100 minus 60 over denominator 60 end fraction space cross times space 100 space equals space 66 2 over 3 percent sign



74 Views

53.

A mixture contains spirit and water in the ratio of 3 : 2. If it contains 3 litre more than water, the quantity of spirit in the mixture is

  • 12 litre

  • 10 litre

  • 9 litre

  • 8 litre


C.

9 litre

Let the quantity of spirit in the mixture  = 3x
            quantity of water in the mixture = 2x
According to the question,
   3x - 2x = 3;  x = 3 litre
∴   Quantity of spirit in the mixture  = 3 x 3 = 9 litre


319 Views

60.

The orthocentre of a triangle is the point where

  • the medians meet

  • the altitudes meet

  • the right bisectors of the sides of triangle meet

  • the bisectors of the angles of triangle meet


B.

the altitudes meet

69 Views

56.

The distance between two places A and B is 60 km. Two cars start at the same time from A and B, travelling at a speed of 35 km/hr and 25 km/hr respectively. If the cars run in the same direction, then they will meet after (in hours):

  • 6.5

  • 6.2

  • 6

  • 6.52


C.

6

As the cars run in the same direction
∴  Relative speed = (35  - 25) km/hr = 10 km/hr
Distance = 60 km
Required time:
   equals space fraction numerator 60 over denominator 35 minus 25 end fraction space equals space 60 over 10 space equals space space 6 space hours

177 Views

54.

If the cost price of 25 pens is equal to the selling price of 20 pens, then the profit percent is:

  • 20%

  • 25%

  • 15%

  • 5%


B.

25%

Shortcut Method:
Required Profit percentage = open parentheses Difference over Sold cross times 100 close parentheses
    equals space open parentheses fraction numerator 25 minus 20 over denominator 20 end fraction space cross times space 100 close parentheses space equals space 25 percent sign

68 Views

57.

The sum of money that will yield ₹ 60/- as simple interest at 6% per annum in 5 years is

  • ₹ 200/-

  • ₹ 225/-

  • ₹ 175/-

  • ₹ 300/-


A.

₹ 200/-

S.I. = ₹ 60
Time (n)=  5 years
R = 6% p.a.
100 S.I. = PRT
100 X 60 = P x 6 x 5
P = ₹ 200/-

68 Views

58.

If x, y and z are real numbers such that (x - 3)2 + (y - 4)2 + (z - 5)2 = 0, then (x + y + z) is equal to

  • -12

  • 0

  • 8

  • 12


D.

12

x - 3 = 0   ⟹  x = 3
y - 4 = 0   ⟹  y = 4
z - 5 = 0  ⟹   z = 5
∴    (x + y + z) = (3 + 4 + 5) = 12

52 Views

55.

A number is decreased by 10% and the resulting number is again decreased by 20%. What is the final percentage of decrease?

  • 25%

  • 26%

  • 27%

  • 28%


D.

28%

Net percentage decrease:
      equals space open parentheses straight x space plus space straight y space minus space xy over 100 close parentheses
equals space 10 space plus space 20 space minus space fraction numerator 10 space cross times space 20 over denominator 100 end fraction
equals space space 30 minus space 2
equals space 28 percent sign

72 Views

59.

If 2 straight x space plus space fraction numerator 1 over denominator 3 straight x end fraction space equals space 5 comma then the value of fraction numerator 5 straight x over denominator 6 straight x squared plus 20 straight x plus 1 end fraction is

  • 1/4

  • 1/6

  • 1/5

  • 1/7


D.

1/7

2 straight x space plus space fraction numerator 1 over denominator 3 straight x end fraction space equals space 5
6 straight x squared plus 1 space equals space 15 straight x
therefore space space space fraction numerator 5 straight x over denominator 6 straight x squared plus 20 straight x plus 1 end fraction space equals space fraction numerator 5 straight x over denominator 15 straight x plus 20 straight x end fraction space equals space fraction numerator 5 straight x over denominator 35 straight x end fraction space equals space 1 over 7
56 Views