Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

53.

The reciprocals of the squares of the numbers 1 1 half space and space 1 1 third are in the ratio:

  • 64 : 81

  • 8 : 9

  • 81 : 64

  • 9 : 8


A.

64 : 81

Required ratio
  equals space 1 over open parentheses 1 begin display style 1 half end style close parentheses squared space colon space 1 over open parentheses 1 begin display style 1 third end style close parentheses squared
equals space 1 over open parentheses begin display style 3 over 2 end style close parentheses squared space colon space 1 over open parentheses begin display style 4 over 3 end style close parentheses squared
equals space fraction numerator 1 over denominator begin display style 9 over 4 end style end fraction space colon space fraction numerator 1 over denominator begin display style 16 over 9 end style end fraction space equals space 4 over 9 thin space colon thin space 9 over 16 space equals space 64 space colon space 81

59 Views

59.

If square root of 3 space equals space 1.732 comma space then the value of fraction numerator 9 plus 2 square root of 3 over denominator square root of 3 end fraction is:

  • 7.169

  • 7.196

  • 5.198

  • 7.296


B.

7.196

fraction numerator 9 plus 2 square root of 3 over denominator square root of 3 end fraction
equals space fraction numerator 9 plus 2 square root of 3 over denominator square root of 3 end fraction space cross times space fraction numerator square root of 3 over denominator square root of 3 end fraction
equals space fraction numerator 9 square root of 3 space plus space 2 cross times 3 over denominator 3 end fraction
equals space 3 square root of 3 space plus space 2
equals space 3 space cross times space 1.732 space plus space 2
equals space 5.196 space plus space 2 space equals space 7.196

38 Views

52.

A dealer allows a discount of 15%. A customer pays an amount of Rs 318.75 for an article. At what price is the article listed?

  • Rs 366.50

  • Rs 375.00

  • Rs 350.00

  • Rs 431.25


B.

Rs 375.00

Let the marked price of the article be Rs x
According to the question,
A dealer allows a discount of 15%. A customer pays an amount of Rs 318

67 Views

58.

The compound interest on Rs 1,000/- at 10% per annum for 3 years (in Rs) is:

  • Rs. 1,331/-

  • Rs. 331/-

  • Rs. 300/-

  • Rs. 1,300/-


B.

Rs. 331/-

1000 space rightwards arrow with 10 percent sign space equals space 100 on top 1100 rightwards arrow with 10 percent sign space equals space 110 on top 1210 rightwards arrow with 10 percent sign space equals space 121 on top 1331
∴  Required interest  = Rs. (100 + 110 + 121) = Rs. 331

45 Views

60.

If straight x space plus space 1 over straight x space equals space 2 comma then the value of straight x to the power of 99 space plus space 1 over straight x to the power of 99 minus 2 is:

  • -2

  • 0

  • 2

  • 4


B.

0

straight x space plus space 1 over straight x space equals space 2,
Put the value of x = 1 as it satisfies the equation,
1 plus 1 over 1 space equals space 2 
therefore space space space space space straight x to the power of 99 space plus space 1 over straight x to the power of 99 space minus space 2 space equals space left parenthesis 1 right parenthesis to the power of 99 space plus space fraction numerator 1 over denominator left parenthesis 1 right parenthesis to the power of 99 end fraction minus 2 space equals space 2 space space minus space 2 space equals space 0

 

38 Views

54.

The average of 15 numbers is 7. If the average of the first 8 numbers is 6.5 and the average of the last 8 number is 8.5. then middle number is

  • 10

  • 23

  • 13

  • 15


D.

15

Sum of all 15 numbers = 15 x 7 = 105
Sum of first 8 numbers  = 6.5 x 8 = 52
Sum of last 8 numbers = 8 x 8.5 = 68
∴ Required Middle Number = 52 + 68 - 105 = 120 - 105 = 15

65 Views

57.

A man travells 3 over 4 th of the distance of his journey by bus, 1 over 6 th by Rickshaw and 2 km on foot. The total distance travelled by the man is

  • 12 km

  • 18 km

  • 20 km

  • 24 km


D.

24 km

Distance travelled by foot:
open parentheses 1 minus 3 over 4 space minus 1 over 6 close parentheses space equals space open parentheses fraction numerator 12 minus 9 minus 2 over denominator 12 end fraction close parentheses space equals space 1 over 12 th
According to the question,
1 over 12 th space equals space 2 space km
∴  Total distance travelled  = (12 x 2) = 24 km

55 Views

51.

Number of composite numbers lying between 67 and 101 is

  • 27

  • 24

  • 26

  • 23


A.

27

A whole number that can be divided exactly by numbers other than 1 or itself is called composite number.
Here are list of composite numbers till 100

Thus, between 67 and 101 there 27 such numbers.

218 Views

55.

A man bought 25 creates of oranges for Rs 10,000/-. He lost 5 crates. In order to earn a total profit of 25% of the total cost, he would have to sell each of the remaining crates at:

  • Rs 650/-

  • Rs 625/-

  • Rs 600/-

  • Rs 575/-


B.

Rs 625/-

Purchased crates = 25
Lost crates = 5 
Net crates = (25 - 5) = 20 crates.
Let he sells remaining crates at Rs. x/-
Now, according to the question,
10 comma 000 space cross times 125 over 100 space equals space 20 space cross times space straight x
straight x space equals space 12500 over 20 space equals space ₹ space 625 divided by negative

94 Views

56.

What is the difference between 0.6 and 0.6%?

  • 5.94

  • 0.594

  • 60

  • 54


B.

0.594

Required difference
       equals space 0.6 space minus space fraction numerator 0.6 over denominator 100 end fraction
equals space 0.6 space minus space 0.006 space equals space 0.594

55 Views