Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

61.

In ΔABC, the medians AD and BE meet at G. The ratio of the areas of ΔBDG and the quadrilateral GDCE is:

  • 1 : 2

  • 1 : 3

  • 2 : 3

  • 3 : 4

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62.

PQRSTU is a cyclic hexagon. Then ∠P + ∠R + ∠T is equal to:

  • 720°

  • 360°

  • 540°

  • 180°

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63.

If straight r space sin space straight theta space equals space 7 over 2 and straight r space cos space straight theta space equals space fraction numerator 7 square root of 3 over denominator 2 end fraction then the value of θ is

  • 30°

  • 45°

  • 60°

  • 75°

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64.

Shashi can do a piece of work in 20 days. Tanya is 25% more efficient than Shashi. The number of days taken by Tanya to do the same piece of work is:

  • 15

  • 16

  • 18

  • 25

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65.

If straight a space plus space 1 over straight b space equals space 1 comma space space space straight b space plus space 1 over straight c space equals space 1, then the value of abc is:

  • 0

  • -1

  • 1

  • ab

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66.

If 2 straight x space minus space fraction numerator 1 over denominator 2 straight x end fraction space equals space 5 comma straight x not equal to 0 then the value of straight x squared space plus space fraction numerator 1 over denominator 16 straight x squared end fraction minus 2 is

  • 19 over 4

  • 23 over 4

  • 27 over 4

  • 31 over 4

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67.

XYZ is a right angled triangle and ∠Y = 90°. If XY = 2.5 cm and YZ = 6 cm, then the circumradius of Δ XYZ is:

  • 6.5 cm

  • 3.25 cm

  • 3 cm

  • 2.5 cm

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68.

In Δ ABC, angle straight B space equals space 5 angle straight C and angle straight A space equals space 3 angle straight C, then the measure of angle straight C is

  • 45°

  • 30°

  • 20°

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69.

The length of shadow of a tower is √3 times that of its length. The angle of elevation of the sun is

  • 45°

  • 30°

  • 60°

  • None of these

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70.

If x is the area, y is the circumference and z is the diameter of circle then the value of straight x over yz is

  • 4 : 1

  • 1 : 4

  • 1 : 2

  • 2 : 1


B.

1 : 4

Area of circle  = πr squared
      straight x space equals space straight pi open parentheses straight z over 2 close parentheses squared
Circumference of circle = πd
rightwards double arrow space space space space straight y space equals space πz
Now, the value of straight x over yz
straight x over yz space equals space fraction numerator straight pi begin display style straight z squared over 4 end style over denominator πz space cross times space straight z end fraction space equals space 1 fourth
therefore space space straight x space colon space yz space equals space 1 space colon space 4


        

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