Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

55.

What number should be added to each of the numbers 55, 100, 65 and 116, so that the resulting numbers are in continued proportion?

  • 20

  • 10

  • 5

  • 15


A.

20

a = 55, b = 100, c = 65 and d = 116
Required number:
            fraction numerator bc minus ad over denominator left parenthesis straight a space plus space straight d right parenthesis space minus space left parenthesis straight b space plus space straight c right parenthesis end fraction
       equals space fraction numerator 100 space cross times space 65 space minus space 55 space cross times space 116 over denominator left parenthesis 55 space plus space 116 right parenthesis space minus space left parenthesis 100 space plus 65 right parenthesis end fraction
equals space fraction numerator 6500 space minus space 6380 over denominator 171 space minus space 165 end fraction
equals space 120 over 6 space equals space 20
            


56.

A batsman makes a score of 111 runs in the 10th match and thus increases his average runs per match by 5. What will be his average after the 10th match?

  • 66

  • 61

  • 62

  • 64


A.

66

Let the average after 10th match be x.
∴  average after 9th match (x - 5).
Now, 
According to the question,
       rightwards double arrow space space space space 10 straight x space minus space 9 left parenthesis straight x minus 5 right parenthesis space equals space 111
rightwards double arrow space space space space 10 straight x space minus space 9 straight x space plus space 45 space equals space 111
rightwards double arrow space space space space space space space straight x space equals space 111 space minus space 45
rightwards double arrow space space space space space space space space straight x space equals space 66


57.

A vendor buys 6 bananas for ₹ 25/- and sells them at 3 for ₹ 20/-. What is his profit percentage?

  • 50%

  • 40%

  • 60%

  • 30%


C.

60%

Shortcut Method:
equals space fraction numerator left parenthesis 6 space cross times space 20 right parenthesis space minus space left parenthesis 25 space cross times space 3 right parenthesis over denominator 25 space cross times space 3 end fraction cross times 100
equals space fraction numerator 120 space minus space 75 over denominator 75 end fraction space cross times space 100
equals space 45 over 3 space cross times space 4 space equals space 15 space cross times space 4 space equals space 60 percent sign


60.

The compound interest earned in two years at 12% per annum is ₹ 10,176/-. What is the sum (in ₹) invested?

  • ₹ 50,000/-

  • ₹ 60,000/-

  • ₹ 40,000/-

  • ₹ 80,000/-


C.

₹ 40,000/-

Let the sum invested be ₹ P.
straight P open square brackets open parentheses 1 plus 12 over 100 close parentheses squared minus 1 close square brackets space equals space 10176
rightwards double arrow space space straight P open square brackets open parentheses 28 over 25 close parentheses squared minus 1 close square brackets space equals space 10176
rightwards double arrow space space straight P open square brackets fraction numerator 784 minus 625 over denominator 625 end fraction close square brackets space equals space 10176
rightwards double arrow space space space straight P left square bracket 159 right square bracket space equals space 10176 space cross times space 625
rightwards double arrow space space space space straight P space equals space space 64 space cross times space 625
rightwards double arrow space space space straight P space equals space ₹ space 40 comma 000 divided by negative


53.

What is the area (in cm2) of a rectangle if its diagonal is 25 cm and one of its sides is 24 cm?

  • 186 cm2

  • 144 cm2

  • 132 cm2

  • 168 cm2


D.

168 cm2


In Δ ABC,
AC2 = AB2 + BC2
252 = AB2 + 242
AB2 = 252 - 242
AB2 = 625 - 576
AB2 = 49
AB = 7
Now, l(length) =24 cm (given ) Breadth (b) = 7 cm
∴  Area of rectangle  = l x b = 7 x 24 = 168 cm2



54.

A shopkeeper marks up his wares by 60% and offers 25% discount. What will be the selling price (in ₹) if the cost price is ₹ 1,600/-?

  • ₹ 1,920/-

  • ₹ 2,000/-

  • ₹ 2,120/-

  • ₹ 2,200/-


A.

₹ 1,920/-

Cost Price = ₹ 1,600
Marked price:
               equals space 1600 space cross times space 160 over 100 space equals space ₹ 2 comma 560 divided by negative  
Selling price:
              equals space 2560 space cross times space fraction numerator left parenthesis 100 minus 25 right parenthesis over denominator 100 end fraction space
equals space 2560 space cross times space 75 over 100 space equals space ₹ space 1 comma 920 divided by negative


59.

A man travelled a distance of 60 km in 7 hours. He travelled partly on foot @ 6km/h and partly on bicycle @ 12 km/h. What is the distance (in km) travelled on foot?

  • 15 km

  • 9 km

  • 48 km

  • 24 km


D.

24 km

Let the distance travelled on foot  = d km
According to the question,
   rightwards double arrow space space space straight d over 6 space plus space fraction numerator 60 minus straight d over denominator 12 end fraction space equals space 7
rightwards double arrow space space space space fraction numerator 2 straight d space plus space 60 space minus space straight d over denominator 12 end fraction space equals space 7
rightwards double arrow space space space space space space straight d space equals space 84 space minus space 60 space equals space 24 space km


58.

Two labourers A and B are paid a total of ₹ 650 per day. If A is paid 160% of what is paid to B, how much (in ₹) is B paid?

  • ₹ 250/-

  • ₹ 400/-

  • ₹ 350/-

  • ₹ 450/-


A.

₹ 250/-

A : B = 160 : 100 = 8 : 5.
Total Wages per day = ₹ 650 
B's wages per day:
          equals space 5 over 13 space cross times space 650
equals space ₹ space 250


51.

What is the quotient when 7251 is divided by 66?

  • 110

  • 109

  • 111

  • 112


B.

109

7251 = 66 x 109 + 57
∴   Quotient = 109


52.

Asif is twice as good as workman as Bashir and together they finish a piece of work in 30 days. In how many days will Asif alone finish the work?

  • 90 days

  • 45 days

  • 60 days

  • 75 days


B.

45 days

Let Asif takes x days to finish the work.
∴  Bashir takes 2x days.
Now,
rightwards double arrow space space space fraction numerator straight A space cross times space straight B over denominator straight A space plus space straight B end fraction space equals space 30
rightwards double arrow space space fraction numerator straight x space cross times space left parenthesis 2 straight x right parenthesis over denominator 3 straight x end fraction space equals space 30
rightwards double arrow space space fraction numerator 2 straight x squared over denominator 3 straight x end fraction space equals space 30
rightwards double arrow space space space straight x space equals space 45 space days