What is expected value of Van’t Hoff factor for K₃ [Fe(CN)₆] in dilute solution?

---

solution:
The dissociative equation for K₃[Fe(CN₆)] can be written as:

${\mathrm{k}}_3 \mathrm{Fe}(\mathrm{CN}{)}_6 \to 3{\mathrm{K}}^{+}+[\mathrm{Fe}(\mathrm{CN}{)}_6{]}^{3-}$
 
therefore , number of particles after dissiociation = 4
so van't hoff factor =4/1 = 4