Calculate the number of unpaired electrons in following gaseous ions: Mn³⁺, Cr³⁺, V³⁺ and Ti³⁺, which one of these is the most stable in aqueous solution?

The number of unpaired electrons can be determined from their electronic configurations and are tabulated below:

Specie	Electronic configuration	No. of unpaired electron
1. Mn³⁺	[Ar] 3d⁴4s⁰	4
2. Cr³⁺	[Ar] 3d³4s⁰	3
3. V³⁺	[Ar] 3d²4s⁰	2
4. Ti³⁺	[Ar] 3d¹4s⁰	1

Out of these, Cr³⁺ is most stable in aqueous solution as its hydration energy is highest
.

894 Views

The d-And-f-Block Elements

Hope you found this question and answer to be good. Find many more questions on The d-And-f-Block Elements with answers for your assignments and practice.

Chemistry I

Browse through more topics from Chemistry I for questions and snapshot.

Calculate the number of unpaired electrons in following gaseous ions: Mn3+, Cr3+, V3+ and Ti3+, which one of these is the most stable in aqueous solution?

The d-And-f-Block Elements

Chemistry I

Calculate the number of unpaired electrons in following gaseous ions: Mn³⁺, Cr³⁺, V³⁺ and Ti³⁺, which one of these is the most stable in aqueous solution?