Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.2x + y = 5 3x + 2y = 8 - Zigya
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Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.
2x + y = 5
3x + 2y = 8


2 x + y = 5
3x + 2y = 8
The given pair of linear equations is
2x + y = 5
3x + 2y = 8
⇒ 2x + y - 5 = 0
3x + 2y - 8 = 0
Here,    a1 = 2, b1 = 1, c, = -5
a2 = 3, b2 = 2, c2 = -8
We see that,

straight a subscript 1 over straight a subscript 2 not equal to straight b subscript 1 over straight b subscript 2

Hence, the given pair of linear equations has a unique solution.
To solve the given equation by cross multiplication method, we draw the diagram below :


2 x + y = 53x + 2y = 8The given pair of linear equations is2x + y = 5
Hence, the required solution of the given pair of linear equation is x = 2, y = 1.

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