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In ∆ABC, we have LM || CB <img class=Wirisformula style=vertical-align: -9px; src=/application/zrc/images/qvar/MAEN10042112-2.png alt=space space AL over AC space equals space AM over AB space space space space space space space space space space space space space... left parenthesis straight i right parenthesis width=138 height=25 align=middle data-mathml=«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#160;«/mo»«mo»§#160;«/mo»«mfrac»«mi»AL«/mi»«mi»AC«/mi»«/mfrac»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mfrac»«mi»AM«/mi»«mi»AB«/mi»«/mfrac»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo»(«/mo»«mi mathvariant=¨normal¨»i«/mi»«mo»)«/mo»«/math»> [Using Basic proportionality theorem] IN ∆ADC, We have LN || CD <img class=Wirisformula style=vertical-align: -9px; src=/application/zrc/images/qvar/MAEN10042112-4.png alt=space AL over AC equals AN over AD space space... left parenthesis ii right parenthesis width=98 height=25 align=middle data-mathml=«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#160;«/mo»«mfrac»«mi»AL«/mi»«mi»AC«/mi»«/mfrac»«mo»=«/mo»«mfrac»«mi»AN«/mi»«mi»AD«/mi»«/mfrac»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo».«/mo»«mo».«/mo»«mo».«/mo»«mo»(«/mo»«mi»ii«/mi»«mo»)«/mo»«/math»> [Using Basic proportionality theorem] From (i) and (ii), we have proved. [Converse of Basic proportionality theorem]