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In the given Fig, two triangles ABC and DBC lie on the same side of base BC. P is a point on BC such that PQ || BA and PR || BD. Prove that: QR || AD.   



In              
By BPT theorem                   

In increment ABC comma space             space PQ parallel to AB

By BPT theorem      CP over BP equals CQ over AQ               ...(i)

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#6 {main}</pre>         PR parallel to BD

rightwards double arrow      By using BPT  CP over BP equals CR over RD            ...(ii)

From (i) and (ii)    space CP over BP equals CP over BP

rightwards double arrow    By converse of BPT,  QR parallel to AD.
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