Find the 60^th term of the AP 8, 10,12, ..., if it has a total of 60 terms and hence find the sum of its last 10 terms.

The given AP is 8, 10, 12, ....

So,

First term =a = 8

Common difference = d = 10-8 =2

We know that n^th term of an AP, a_n = a + (n - 1)

60^th term of the given AP = a₆₀ = 8 +( 60-1) x  2 = 8 + 59 x 2 = 8 + 118 = 126

Therefore, the 60^th term of the given AP is 126

It is given that the AP has a total of 60 terms. So, in order to find sum of last n terms. we take

First term, A = 126
Common difference, D = -2
Now,