Suppose 2 kg of sugar contains 9 x 106 crystals. How many sugar crystals are there in (i) 5 kg of sugar? and (ii) 1.2 kg of sugar?
Solution: Let the required number of sugar crystals be x in 5 kg of sugar.
We have:
(i)
Weight of sugar |
Number of sugar crystals |
2 |
9 x 106 |
5 |
X |
(ii) Let the number sugar crystals in 1.2 kg of sugar be y.
∴We have:
Weight of sugar |
Number of sugar crystals |
2 |
9 x 106 |
1.2 |
y |