Construct the following quadrilateral.Rhombus BENDBN = 5.6 cmDE = 6.5 cm - Zigya
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Construct the following quadrilateral.
Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm


Steps of construction:
I. Draw a line segment DE = 6.5 cm.
II. Draw perpendicular bisector PQ of DE such that M being the mid-point of DE.
III. With centre M and radius = 1 half cross times 5.6 space cm
     = 2.8 cm, draw arcs to intersect PQ at B and N.
IV. Join ND, NE, BE and BD.
Thus, BEND is the required rhombus.

Steps of construction:I. Draw a line segment DE = 6.5 cm.II. Draw p



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