A carboxylic acid (molecular formula C2H402) reacts with an alcohol in the presence of an acid catalyst to form a compound 'X'. The alcohol on oxidation with alkaline KMnO4 followed by acidification gives the same carboxylic acid C2H402. Write the name and structure of
(i) carboxylic acid, (ii) alcohol and (iii) the compound 'X'.
The chemical name of given carboxylic acid is ethanoic acid. When ethanoic acid reacts with the acid in the presence of an acid such as sulphuric acid as a catalyst to produce the ester, (ethyl ethanoate).
i) Carboxylic acid = Ethanoic acid
ii) alcohol = Ethyl alcohol
iii) Compound X = ethyl ethanoate
