While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after the experiment = 35 g
The percentage of water absorbed by raisins is:
$begin inline style fraction numerator 40 straight g space minus space 35 straight g over denominator 35 straight g end fraction end style space cross times space 100$
$fraction numerator 40 straight g space minus space 35 straight g over denominator 40 straight g end fraction space cross times space 100$
$fraction numerator 8 straight g space minus space 5 straight g over denominator 8 straight g end fraction space cross times space 100$
$fraction numerator 8 straight g space minus space 5 straight g over denominator 8 straight g end fraction space cross times space 100$

fraction numerator 8 straight g space minus space 5 straight g over denominator 8 straight g end fraction space cross times space 100

The percentage of water absorbed by raisins is calculated by using the formula

$fraction numerator straight W subscript 2 space minus straight W subscript 1 over denominator straight W subscript 1 end fraction space cross times space 100$

where, W₂ is the weight of wet resin and W₁ is the weight of dry resin.

1147 Views

Life Processes

Hope you found this question and answer to be good. Find many more questions on Life Processes with answers for your assignments and practice.

Science

Browse through more topics from Science for questions and snapshot.