Define escape velocity. Derive an expression for escape velocity. Find the value of escape velocity. - Zigya
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Define escape velocity. Derive an expression for escape velocity. Find the value of escape velocity.


Escape velocity is minimum velocity with which a body must be thrown upward so that it may just escape.
Expression for escape velocity:
Let a body of mass m be escaped from gravitational field of the earth. During the course of motion, let at any instant body be at a distance r from the centre of the earth.

Escape velocity is minimum velocity with which a body must be thrown
The gravitational force between body and the earth is,
                               straight F equals GMm over straight r squared dr
and work done to raise the body by distance dr is,
                             space space dW equals GMm over straight r squared dr
   Total work done W in raising the body from the surface of the earth to infinity is,
                             straight W equals integral subscript straight R superscript infinity GMm over straight r squared dr equals GMm open square brackets negative 1 over straight r close square brackets subscript straight R superscript infinity
                                 equals GMm open square brackets negative 1 over infinity plus 1 over straight R close square brackets equals GMm over straight R

If we throw the body upward with a velocity ve, then work done to raise the body from surface of the earth to infinity is done by kinetic energy,
                                 GMm over straight R equals 1 half mv subscript straight e squared
or                                straight v subscript straight e equals square root of fraction numerator 2 GM over denominator straight R end fraction end root space equals space square root of 2 gR end root
or                                 straight v subscript straight e equals square root of 2 gR end root
Substituting the values, g = 9.81m/sec and R = 6.4 x 106m, we have,
  straight v subscript straight e equals square root of 9.81 cross times 6.4 cross times 10 to the power of 6 end root space equals space 11200 space straight m divided by straight s
       equals 11.2 space km divided by straight s

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