Discuss one-dimensional elastic collision. Obtain an expression for their velocities after collision. - Zigya
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Discuss one-dimensional elastic collision. Obtain an expression for their velocities after collision.


One-dimensional elastic collision is the collision in which the colliding bodies continue to move along the same straight line after collision.
Consider two bodies A and B of masses m1 and m2 moving along the same straight line with velocities u1 and u2 respectively.

One-dimensional elastic collision is the collision in which the colli

Let the two bodies collide elastically and let and v2 be the velocities of two bodies after collision. Since collision is elastic collision, therefore, their momentum and kinetic energy remain conserved.
By conservation of momentum,
                straight m subscript 1 straight u subscript 1 plus straight m subscript 2 straight u subscript 2 equals straight m subscript 1 straight v subscript 1 plus straight m subscript 2 straight v subscript 2
or              straight m subscript 1 left parenthesis straight u subscript 1 minus straight v subscript 1 right parenthesis space equals space straight m subscript 2 left parenthesis straight v subscript 2 minus straight u subscript 2 right parenthesis                      ...(1)
By conservation of kinetic energy
                   1 half straight m subscript 1 straight u subscript 1 superscript 2 plus 1 half straight m subscript 2 straight u subscript 2 superscript 2 equals 1 half straight m subscript 1 straight v subscript 1 superscript 2 plus 1 half straight m subscript 2 straight v subscript 2 superscript 2
or                space space space space space space space space straight m subscript 1 left parenthesis straight u subscript 1 superscript 2 minus straight v subscript 1 superscript 2 right parenthesis space equals space straight m subscript 2 left parenthesis straight v subscript 2 superscript 2 minus straight u subscript 2 superscript 2 right parenthesis             ...(2)
Dividing (2) by (1), we get,
         space space space space space space space space space space space space space space space space space space space left parenthesis straight u subscript 1 plus straight v subscript 1 right parenthesis equals left parenthesis straight v subscript 2 plus straight u subscript 2 right parenthesis
or                             space space space straight v subscript 2 equals straight u subscript 1 minus straight u subscript 2 plus straight v subscript 1                      ...(3)
Substituting (3) by (1), we get
                           straight m subscript 1 left parenthesis straight u subscript 1 minus straight v subscript 1 right parenthesis space equals straight m subscript 2 left parenthesis straight u subscript 1 minus straight u subscript 2 plus straight v subscript 1 minus straight u subscript 2 right parenthesis
or                space space space straight m subscript 1 straight u subscript 1 minus straight m subscript 1 straight v subscript 1 equals straight m subscript 2 straight u subscript 1 minus 2 straight m subscript 2 straight u subscript 2 plus straight m subscript 2 straight v subscript 1
or                     left parenthesis straight m subscript 1 plus straight m subscript 2 right parenthesis straight v subscript 1 equals left parenthesis straight m subscript 1 plus straight m subscript 2 right parenthesis straight u subscript 1 minus 2 straight m subscript 2 straight u subscript 2
or                   straight v subscript 1 equals fraction numerator left parenthesis straight m subscript 1 minus straight m subscript 2 right parenthesis straight u subscript 1 plus 2 straight m subscript 2 straight u subscript 2 over denominator straight m subscript 1 plus straight m subscript 2 end fraction
Substituting for straight v subscript 1 in equation (3), we get
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                            equals fraction numerator left parenthesis straight m subscript 2 minus straight m subscript 1 right parenthesis straight u subscript 2 plus 2 straight m subscript 1 straight u subscript 1 over denominator straight m subscript 1 plus straight m subscript 2 end fraction



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