A jet airplane travelling at the speed of 500 km/hr ejects its products of combustion at the speed of 1500 km/hr relative to the jet plane. What is the speed of the later with respect to an observer on the ground?

Let the velocity of ejecting gases with respect to ground be $straight V subscript straight g$ .

Velocity of jet plane, $straight V subscript straight j equals plus 500 space km divided by hr$

Velocity of ejected products w.r.t. jet plane,

$straight V subscript gj equals negative 1500 space km divided by hr.$

Now, relative velocity of ejecting gases w.r.t the jet plane is given by,

$straight V subscript gj equals straight V subscript straight g minus straight V subscript straight j$

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$equals negative 1500 plus 500 space equals space minus 1000 space km divided by hr$

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