State Gauss s law in electrostatics. Use this law to derive an expression for the electric field due to an infinitely long straight wire of linear charge density A cm–1. - Zigya
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State Gauss's law in electrostatics. Use this law to derive an expression for the electric field due to an infinitely long straight wire of linear charge density A cm–1.


Gauss’s law in electrostatics: It states that total electric flux over the closed surface S in vacuum is 1 over straight epsilon subscript 0 times the total charge (q) contained in side S.
therefore                     straight ϕ subscript straight E space equals space contour integral for straight s of straight E with rightwards arrow on top. space ds with rightwards arrow on top space equals space straight q over straight epsilon subscript 0
Electric field due to an infinitely long straight wire.
Let an infinitely long line charge having linear charge density X. Assume a cylindrical Gaussian surface of radius r and length 1 coaxial with the line charge to determine its electric field at distance r.
By symmetry, the electric field E has same magnitude at each point of the curved surface S1 and is directed radially outward. So angle at surfaces between dS with rightwards arrow on top space and space straight E with rightwards arrow on top is zero, and angle of stack dS subscript 2 with rightwards arrow on top comma space space stack dS subscript 3 with rightwards arrow on top with straight E with rightwards arrow on top at straight S subscript 2 space and space straight S subscript 3 are 90 degree.

Gauss’s law in electrostatics: It states that total electric flux o
Total flux through the cylindrical surface,
contour integral straight E with rightwards arrow on top. ds with rightwards arrow on top space equals space contour integral for straight S subscript 1 of straight E with rightwards arrow on top. space stack dS subscript 1 with rightwards arrow on top space plus space contour integral for straight S subscript 2 of stack straight E. with rightwards arrow on top space stack dS subscript 2 with rightwards arrow on top plus space contour integral for straight S subscript 3 of straight E with rightwards arrow on top. space stack dS subscript 3 with rightwards arrow on top

space equals space contour integral for straight S subscript 1 of EdS subscript 1. space cos space 0 degree space plus space contour integral for straight S subscript 2 of EdS subscript 2. space cos space 90 degree plus space contour integral for straight S subscript 3 of EdS subscript 3. space cos space 90 degree
equals space straight E space contour integral space dS subscript 1 space equals space straight E space cross times space 2 πrl
Since λ is the charge per unit length and l is the length of the wire, Thus, the charge enclosed
q = λl
According to Gaussian law,

Gauss’s law in electrostatics: It states that total electric flux o
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