Ultraviolet light is incident on two photosensitive materials having work functions W₁ and W₂ (W₁ > W₂). In which case will the kinetic energy of the emitted electrons be greater? Why?

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According to the formula,

K.E. of photoelectron = hv – W
That is, more is the kinetic energy less would be the work function or vice-cersa. 

Given,   W₁ > W₂ (W₁ and W₂ are the work function of material respectively.)

Since, W₂ is lesser than W₁ thus, the kinetic energy of the emitted electrons for the photoelectric material having work function W₂ will be greater.