An a.c. source of voltage V = Vm sin ωt is connected, one-by-one, to three circuit elements X, Y and Z. It is observed that the current flowing in them,(i) is in phase with applied voltage for element X.(ii) lags the applied voltage, in phase, by π/2 for element Y.(iii) leads the applied voltage, in phase, by π/2 for element Z. Identify the three circuit elements.Find an expression for the (a) current flowing in the circuit, (b) net impedance of the circuit, when the same a.c. source is connected across a series combination of the elements X, Y and Z. (c) If the frequency of the applied voltage is varied, set up the condition of frequency when the current amplitude in the circuit is maximum. Write the expression for this current amplitude. - Zigya
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An a.c. source of voltage V = Vm sin ωt is connected, one-by-one, to three circuit elements X, Y and Z. It is observed that the current flowing in them,
(i) is in phase with applied voltage for element X.
(ii) lags the applied voltage, in phase, by π/2 for element Y.
(iii) leads the applied voltage, in phase, by π/2 for element Z. Identify the three circuit elements.
Find an expression for the (a) current flowing in the circuit, (b) net impedance of the circuit, when the same a.c. source is connected across a series combination of the elements X, Y and Z. (c) If the frequency of the applied voltage is varied, set up the condition of frequency when the current amplitude in the circuit is maximum. Write the expression for this current amplitude.


(a) (i) Circuit element X is resistance R.
(ii) Circuit element Y is capacitance C.
(iii) Circuit element Z is capacitance L.
(a) I = Im sin ωt (For R)
I = Im sin left parenthesis ωt minus straight pi divided by 2 right parenthesis (For L)
I = Im sin (ωt plus straight pi divided by 2) (For C)

(b) Let a resistance R, capacitance C and inductance L be connected in series to a source of alternating e.m.f., as shown in figure (a). Since R, L and C are in series, therefore, current at any instant through three elements has the same amplitude and phase. Let it be given as
I = I0 sin ωt
However, voltage across each element bears a different phase relationship with the current. Now,
(i) The maximum voltage across R is
stack straight V subscript straight R with rightwards arrow on top space equals space stack straight I subscript 0 with rightwards arrow on top straight R

(a) (i) Circuit element X is resistance R.(ii) Circuit element Y is
Fig. (a).
In Fig.(b), current phasor stack straight I subscript 0 with rightwards arrow on top. is represented along OX.

(a) (i) Circuit element X is resistance R.(ii) Circuit element Y is
Fig.(b)
As stack straight V subscript straight R with rightwards arrow on top is in phase with current, it is represented by the vector straight O with rightwards arrow on top straight A comma salong OX.
(ii) The maximum voltage across L is
stack straight V subscript straight L with rightwards arrow on top space equals space stack straight I subscript 0 with rightwards arrow on top space straight X subscript straight L
As voltage across the inductor leads the current by 90°, it is represented by OB with rightwards arrow on top along OY, 90° ahead of stack straight I subscript 0 with rightwards arrow on top.
(iii) The maximum voltage across C is
stack straight V subscript straight C with rightwards arrow on top space equals space stack straight I subscript 0 with rightwards arrow on top space straight X subscript straight C
As voltage across the capacitor lags behind the alternating current by  90°, it is represented by OC with rightwards arrow on top rotated clockwise through 90° from the direction of stack straight I subscript 0 with rightwards arrow on top. OC with rightwards arrow on top is along OY' is along OY'.
As the voltage across L and C have a phase difference of 180°, the net reactive voltage is open parentheses stack straight V subscript straight L with rightwards arrow on top space minus stack straight V subscript straight C with rightwards arrow on top close parentheses comma assuming that stack straight V subscript straight L with rightwards arrow on top space greater than thin space stack straight V subscript straight C with rightwards arrow on top.
In figures (a) and (b), it is represented by stack OB apostrophe with rightwards arrow on top.
 The resultant of the resultant of OA with rightwards arrow on top and stack OB apostrophe with rightwards arrow on top is the diagonal OK with rightwards arrow on top of the rectangle OAKB'. Hence the vector sum of stack straight V subscript straight R with rightwards arrow on top comma space stack straight V subscript straight L with rightwards arrow on top space and space stack straight V subscript straight C with rightwards arrow on top is phasor stack straight E subscript 0 with rightwards arrow on top represented by OK with rightwards arrow on top comma making an angle straight ϕ with current phasor stack straight I subscript 0 with rightwards arrow on top.
   As                                OK space equals space square root of OA squared plus OB apostrophe squared end root
therefore                                     straight E subscript 0 space equals space square root of straight V subscript straight R superscript 2 plus open parentheses straight V subscript straight L minus straight V subscript straight C close parentheses squared end root
space space space space space space equals space square root of left parenthesis straight I subscript 0 space straight R right parenthesis squared plus left parenthesis straight I subscript 0 space straight X subscript straight L space minus straight I subscript 0 straight X subscript straight C right parenthesis squared end root
                           straight E subscript 0 space equals space straight I subscript 0 square root of straight R squared plus left parenthesis straight X subscript straight L minus straight X subscript straight C right parenthesis squared end root

The total effective resistance of RLC circuit is called Impedance of the circuit. It is represented by Z, where
(c) When the current amplitude in the circuit is maximum then XL = Xc.
2 πf subscript 0 straight L space equals space fraction numerator 1 over denominator 2 πf subscript 0 straight C end fraction
      straight f subscript 0 space equals space fraction numerator 1 over denominator 2 straight pi square root of LC end fraction
where f0 is called the resonant frequency.
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