Deduce the condition for balance in a Wheatstone bridge. Using the principle of Wheatstone bridge, describe the method to determine the specific resistance of a wire in the laboratory. Draw the circuit diagram and write the formula used. Write any two important precautions you would observe while performing the experiment.  - Zigya
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Deduce the condition for balance in a Wheatstone bridge. Using the principle of Wheatstone bridge, describe the method to determine the specific resistance of a wire in the laboratory. Draw the circuit diagram and write the formula used. Write any two important precautions you would observe while performing the experiment. 


Four resistances P, Q, R and S are connected to form quadrilateral ABCD. A galvanometer G is connected between B and D. A battery is connected between A and C. The resistances are so adjusted that no current flows in the galvanometer G. The same current will flow in arms AB and BC. Similarly current I2 flows in arms AD and DC.

Four resistances P, Q, R and S are connected to form quadrilateral AB

Applying Kirchhoff’s second law for mesh ABCD,
I1P – I2R = 0
or, J1P = I2R ...(i)
For mesh BCDB,
I1Q – I2S = 0
or, I1Q = I2S ...(ii)
Dividing (i) by (ii), we get
straight P over straight Q equals straight R over straight S
This is the balanced condition of the Wheatstone bridge.
Measurement of specific resistance: Slide wire or meter bridge is a practical form of Wheatstone bridge.

Four resistances P, Q, R and S are connected to form quadrilateral AB
In the figure X is unknown resistor and R.B is resistance box. After inserting the key k, jockey is moved on wire AC till galvanometer shows no deflection (point B). If k is the resistance per unit length of wire AC.
                 P = resistance of AB = kl
                 Q = resistance of BC = k(100 - l)
therefore           straight R over straight X space equals space straight P over straight Q space equals space fraction numerator kl over denominator straight k left parenthesis 100 minus straight l right parenthesis end fraction

or,               straight X space equals space fraction numerator left parenthesis 100 minus straight l right parenthesis space straight R over denominator straight l end fraction
If r is the radius of wire and l be its length, then its resistivity will be
straight rho space equals space fraction numerator ΧA over denominator straight l apostrophe end fraction space equals space fraction numerator πr squared straight X over denominator straight l apostrophe end fraction

Precautions: (i) The null point should lie in the middle of the wire.
(ii) The current should not be allowed to flow in the wire for a long time.





 



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