If δ1 and δ2 be the angles of dip observed in two planes at right angles to each other and δ is the true angle of dip, then prove that
cot2 δ1 + cot2 δ2 = cot2 δ
Let δ2 be the (apparent) dip in the second plane. The angle made by this plane with the magnetic meridian will be (90° – θ).
Effective horizontal component in this plane is BH cos (90° – θ) i.e., BH sin θ. The vertical component will be Bv only.
or, ...(ii)
Squaring and adding equation (i) and (ii), we get
or,
or, Proved