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Sketch the graphs showing variation of stopping potential with frequency of incident radiations for two photosensitive materials A and B having threshold frequencies straight nuA > straight nuB.
(i) In which case is the stopping potential more and why?
(ii) Does the slope of the graph depend on the nature of the material used? Explain.


Graph showing the variation of stopping potential with frequency of incident radiations:



From the above graph, we can observe that,

i) The stopping potential is inversely proportional to the threshold frequency. Hence, the stopping potential is higher for metal B.

ii)The slope of the graph does not depend on the nature of the material used:

We know that,

straight K subscript max space equals space hν space minus straight ϕ subscript straight o space equals space eV subscript straight o
Dividing the equation throughout by e, we get

hν over straight e minus ϕ subscript o over e space equals space V subscript o
On comparing the above equation with the straight line equation, we get

Slope of the graph = straight h over straight e
That is, the slope of the graph does not depend on the nature of the material used.

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