a) Deduce the expression, N = N0 e−λt, for the law of radioactive decay. (b) (i) Write symbolically the process expressing the β+ decay of  . Also write the basic nuclear process underlying this decay. (ii) Is the nucleus formed in the decay of the nucleus  , an isotope or isobar? - Zigya
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a) Deduce the expression, N = N0 e−λt, for the law of radioactive decay.

(b) (i) Write symbolically the process expressing the β+ decay of Na presubscript 11 presuperscript 22 . Also write the basic nuclear process underlying this decay.

(ii) Is the nucleus formed in the decay of the nucleus Na presubscript 11 presuperscript 22 , an isotope or isobar?


As per the law of radioactive decay, we have

where,

N = Number of nuclei in the sample

ΔN = Amount of nuclei undergoing decay

Δt = Time taken for decay 

So, where λ is Decay constant or disintegration constant.
Δt = 0

 

(b)

(i) The β+ decay for  is given below:

A proton is converted into neutron if, the unstable nucleus has excess protons than required for stability.

In the process, a positron e+ (or a β+) and a neutrino ν are created and emitted from the nucleus.

p → n + β+ + ν

This process is called beta plus decay.

(ii) The nucleus so formed is an isobar of  because the mass number is same, whereas the atomic numbers are different.

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