Discuss the shape of ethane molecule. 


In ethane molecule, both the carbon atoms are in sp3 hybrid state. In its formation, one hybrid orbital of one carbon atom overlaps with one sp3 hybrid of second carbon atom along the internuclear axis to form a sigma (σ;) C – C bond. The remaining three sp3 hybrid orbitals of each carbon atom overlap with Is orbital of hydrogen atom axially to form six sigma C – H bonds.



The length of C – C bond in ethane is 154 pm (or 1.54 Å) and that of each C – H bond is 109 pm (or 1.09 Å).

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Discuss the shape of ethylene (first member of alkenes).


In ethene molecule, each carbon atom undergoes sp2 hybridisation. One sp2 hybrid orbital of one carbon atom overlaps axially with one sp2 hybrid orbital of the other carbon atom to form sigma (σ;) C – C bond. The other two sp2 hybrid orbitals of each carbon atom overlap axially with Is orbital of the hydrogen atom to form sigma (σ;) C – H bonds. The unhybridised p-orbitals of the two carbon atoms overlap sidewise with each other to form a weak  bond, The  bond consists of two  electron clouds which lie above and below the plane of carbon and hydrogen atoms. 



Thus, ethylene molecule consists of four sigma C – H bonds, one sigma C – C bond and one ; the bond between carbon-carbon atom. The bond length of carbon-carbon double bond of ethylene is 134 pm (1.34 Å).
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Write the state of hybridisation of carbon in the following compounds and shapes of each of the molecules:
(a) H2C = O,    (b) CH3F,     (c) HC = N.


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Discuss the shape of methane molecule. 


In methane molecule, carbon atom undergoes sp3 hybridisation. Each sp3 hybrid orbital overlaps with Is orbital of hydrogen atom along the internuclear axis to form σ; bond each.
In this type



The four C – H bonds are directed towards the four corners of a regular tetrahedron. So methane has a tetrahedral structure. Each H – C – H bond angle is of 109° – 28'. Each C –H bond length is 109 pm (1.09 Å).
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How much σ; and straight pi; bonds are present in each of the following molecules:
(i) HC ≡ C – CH = CH – CH3
(ii) CH2 = C = CH – CH3



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