Find mean, median and mode of the following data:

Classes

Frequency

0 - 50

2

50 - 100

3

100 - 150

5

150 - 200

6

200 - 250

5

250 - 300

3

300 - 350

1



From the table,   |I. Finding Mean :
Now, 150 - 200 is the class wh

From the table,   straight n equals space sum from blank to blank of straight f subscript straight i equals 25 rightwards double arrow straight n over 2 equals 12.5 comma space straight a space equals space 175 comma space straight h space equals space 75
|
I. Finding Mean :

Mean space equals space straight a space plus fraction numerator begin display style sum from blank to blank of end style straight f subscript straight i straight u subscript straight i over denominator begin display style sum from blank to blank of end style straight f subscript straight i end fraction cross times straight h
space space space space space space space space equals space 175 plus fraction numerator negative 3 over denominator 25 end fraction cross times 50
space space space space space space space space equals space 175 minus 6 equals 169
Now, 150 - 200 is the class whose cumulative frequency 16 is greater than straight n over 2 equals 12.5. space space  

Therefore, 150 - 200 is the median class. Thus, the lower limit (l) of the median class is 150.

II. Finding median:

Median space equals space straight l plus fraction numerator open parentheses begin display style straight n over 2 end style minus cf close parentheses over denominator straight f end fraction cross times straight h
space space space space space space space space space equals space 150 plus open parentheses fraction numerator 12.5 minus 10 over denominator 6 end fraction close parentheses cross times 50
III. Finding mode:
Mode space equals space l italic space plus open square brackets fraction numerator straight f subscript 1 straight f subscript 0 over denominator 2 straight f subscript 1 minus straight f subscript 0 minus straight f subscript 2 end fraction close square brackets cross times straight h
equals space 150 plus open square brackets fraction numerator 6 minus 5 over denominator 2 cross times 6 minus 5 minus 5 end fraction close square brackets cross times 50
equals space 150 equals 1 half cross times 50

= 150 + 25 = 175


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 The following table gives the daily income of 50 workers of a factory :

Daily income (in Rs.)

No. of Workers

100-120

12

120-140

14

140-160

8

160-180

6

180-200

10

Find the Mean, Mode and Median of the above data.


C.I.

xi

fi

fiixi

c.f

100-120

110

12

1320

12

120-140

130

14

1820

26

140-160

150

8

1200

34

160-180

170

6

1020

40

180-200

190

10

1900

50

 

Σfi = 50

 

Σfixi = 7260

 

left parenthesis straight i right parenthesis space Mean space open parentheses top enclose straight x close parentheses equals fraction numerator begin display style sum from blank to blank of end style straight f subscript straight i straight x subscript straight i over denominator begin display style sum from blank to blank of end style straight f subscript straight i end fraction equals 7260 over 50 equals 145.2
(ii) Here the max. class frequency is 14, and the class corresponding to this frequency is 120-140.

therefore Model class is 120 - 140, therefore space space straight l space equals space 120 comma space Class size h = 20

f= freq. of the model class = 14
f0 = 12,   f= 8

therefore space space M o d e space equals space l italic plus open square brackets fraction numerator f subscript italic 1 italic minus f subscript italic 0 over denominator italic 2 f subscript italic 1 italic minus f subscript italic 0 italic minus f subscript italic 2 end fraction close square brackets italic cross times h
italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic equals italic space italic 120 italic plus fraction numerator open parentheses italic 14 italic minus italic 12 close parentheses italic cross times italic 20 over denominator italic 2 italic cross times italic 14 italic minus italic 12 italic minus italic 8 end fraction
italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic equals italic 120 italic plus fraction numerator italic 2 italic cross times italic 20 over denominator italic 8 end fraction italic equals italic 125
italic space
left parenthesis iii right parenthesis space Here space straight n over 2 equals 25 which lies in the class 120 - 140
therefore space l = 120. c.f. = 12, f = 14, h = 20

therefore space thin space M e d i a n space equals space l space plus open square brackets fraction numerator begin display style n over 2 end style minus c. f. over denominator f end fraction close square brackets cross times h
space space space space space space space space space space space space space space equals space 120 plus fraction numerator 13 cross times 20 over denominator 14 end fraction
space space space space space space space space space space space space space space equals 120 plus 130 over 7 equals 120 plus 18.6
space space space space space space space space space space space space space space equals space 138.6
Hence, mean = 145.2
    mode = 125
  median = 138.6
1455 Views

The table given below shows the frequency distribution of the scores obtained by 200 candidates in a BCA examination.

Score

No. of candidates

200-250

30

250-300

15

300-350

45

350-400

20

400-450

25

450-500

40

500-550

10

550-600

15

Draw cumulative frequency curves by using (i) 'less than series', (ii) 'more than series'.


e assume a class interval 150-200 prior to the first class interval 200-250 wtih zero frequency.
Cumulative frequency distribution [Less than Series]

Scroe

c.f.

Less than 200

0

Less than 250

30

Less than 300

45

Less than 350

90

Less than 400

110

Less than 450

135

Less than 500

175

Less than 550

185

Less than 600

200 


Now, we plot the points : (200, 0), (250, 30), (300, 45), (350, 90), (400, 110), (450, 135), (500, 175), (550, 185), (600, 200).


e assume a class interval 150-200 prior to the first class interval 2

More than Series

Scroe

c.f.

More than 200

200

More than 250

170

More than 300

155

More than 350

110

More than 400

90

More than 450

65

More than 500

25

More than 550

15

More than 600

0

Now, we plot the pts.: (200, 200), (250,170), (300,155), (350,110), (400, 90), (450, 65), (500, 25), (550, 15) and (600, 0).


e assume a class interval 150-200 prior to the first class interval 2

409 Views

Draw both types of cumulative freqneucy curve on the same graph paper and then determine the median.

Marks obtained

No. of students

50-60

4

60-70

8

70-80

12

80-90

6

90-100

6


c.f. distribution table :

Marks

No. of students

c.f. (Less than)

c.f (More tlian)

       

50-60

4

4

36

60-70

8

12

32

70-80

12

24

24

80-90

6

30

12

90-100

6

36

6

Now, we plot the points (60,4), (70,12), (80,24), (90,30), (100,36), for less than series.
And. (50,36), (60,32), (70,24), (80,12), (90,6) for more than series.
The two curves drawn intersect each other at point, say P. Through this point P, draw a vertical line, which meets x-axis at 76.
So, median = 76


c.f. distribution table :

Marks


No. of students


c.f. (Less than)

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Draw 'less than' and 'more than' ogive curve from the following and indicate the value of median.

Marks

No. of students (f)

0-5

7

5-10

10

10-15

20

15-20

13

20-25

12

25-30

10

30-35

14

35-40

9


 c.f. distribution

Marks

No. of students

c.f. (Less than)

c.f (More than)

0-5

7

7

95

5-10

10

17

88

10-15

20

37

78

15-20

13

50

58

20-25

12

62

45

25-30

10

72

33

30-35

14

86

23

35-40

9

95

9

Now we plot the points (5,7), (10,17), (15,37), (20, 50), (25, 62), (30, 72), (35, 86), (40, 95) for less than series. And (0,95), (5,88), (10,78), (15,58), (20, 45), (25,33), (30,23), (35,9) for more than series.


 c.f. distribution

Marks


No. of students


c.f. (Less than)


c.f

The two curves drawn intersect each other at P. Through this P, draw a vertical line, which meets the x-axis at 20. So median = 20.

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