Write the molecular formula of first two members of homologous series having functional group –Cl.
First two members of homologous series having functional group –Cl:
a. CH3Cl (Chloromethane)
b. CH3CH2Cl (Chloroethane)
Two carbon compounds X and Y have the molecular formula C4H8 and C5H12 respectively. Which one of these is most likely to show addition reaction? Justify your answer. Also, give the chemical equation to explain the process of addition reaction in this case.
C4H8 is an unsaturated hydrocarbon, i.e. butene (alkene) and C5H12 is a saturated hydrocarbon, i.e. pentane (alkane).
Unsaturated compounds undergo addition reaction at the multiple bonds.
For example, ethene reacts with in presence of Pd and Ni gives ethane.
Complete the following chemical equations:
(i) CH3COOC2H5+NaOH →
(ii) CH3COOH+NaOH →
(iii) C2H5OH+CH3COOH 
(i) CH3COOC2H5+NaOH → CH3COONa + C2H5OH
(ii) CH3COOH+NaOH → CH3COONa + H2O
(iii) C2H5OH+CH3COOH 
CH3COOC2H5 + H2O
An element P (atomic number 20) reacts with an element Q (atomic number 17) to form a compound. Answer the following questions giving the reason :
Write the position of P and Q in the Modern Periodic Table and the molecular formula of the compound formed when P reacts with Q.
Atomic number of element P is 20
electronic configuration = 2, 8, 8, 2
Valence electron =2
Atomic number of element Q is 17
electronic configuration Q = 2, 8, 7
Valence electron = 1
When P reacts with Q, it looses the two valence electrons (valency 2). These two valence electrons are accepted by two Q atoms (valency 1). Hence, the formula of the compound formed between P and Q is PQ2.
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