Here,
Current flowing through the bulb, I = 4 A
Voltage, V = 12 V
Time, t = 10 min = 600 s
Energy transferred = Vlt
= 12 x 4 x 600
= 28800 J
Given,
Current flowing, I = 5 A
Resistance of the resistor, R = 2 Ω
Time, t = 30 min = 1800 s
Energy transferred = I2Rt
= (5)2 x 2 x 1800
= 9 x 104 J.
100 J of heat are produced each second in a 4 Ω resistance. Find the potential difference across the resistor.
An electric bulb is connected to a 220 V generator. The current is 0.50 A. What is the power of the bulb?
Here,
Ptential of the generator, V = 220 V
Current flowing across the electric bulb, I = 0.50 A
Therefore,
Power of bulb, P = VI
= 220 V x 0.50 A
= 110 W.
Here, we have
Energy consumed = P x t
= 0.4 kW x 240 h
= 96 kWh
Cost of the energy to operate refrigerator at a rate of Rs 3.00 per kWh = 96 x 3.00 = Rs 288.00.