CBSE
Gujarat Board
Haryana Board
Class 10
Class 12
A uniform force of (3Â iÂ +Â j) N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2Â iÂ +Â k) m to position ( 4Â iÂ + 3Â jÂ -Â k) m. The work done by the force on the particle is,
9 J
6 J
13 J
15 J
A.
9 J
Given,
Force, F = 3Â i +Â j_{}r_{1} = ( 2 i + k) m
r_{2} = (4 i + 3 j - k) m
Therefore,
S = r_{2} - r_{1}
Â Â
Therefore,
W = F. s
Â Â = (3i + j). (2 i +3j - 2k)
Â Â = 3 x2 + 3x0
Â Â = 6 + 3 = 9 J
Given,
Force, F = 3Â i +Â j_{}r_{1} = ( 2 i + k) m
r_{2} = (4 i + 3 j - k) m
Therefore,
S = r_{2} - r_{1}
Â Â
Therefore,
W = F. s
Â Â = (3i + j). (2 i +3j - 2k)
Â Â = 3 x2 + 3x0
Â Â = 6 + 3 = 9 J