Four point masses, each of value m, are placed at the corners of a square ABCD of side A. The moment of inertia through A and parallel to BD is
m
2m
√m
√m
D.
√m
I = 2m (
A thin circular ring of mass m and radius R is rotating about its axis with a constant angular velocity ω. Two objects each of mass M are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity ω′
A.
A force of acts on O, the origin of the coordinate system. The torque about the point (1, −1) is
C.
Angular momentum of the particle rotating with a central force is constant due to
Constant Force
Constant linear momentum
Zero Torque
Zero Torque
C.
Zero Torque