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Factorisation

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Mathematics

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Class 10 Class 12

Factorise 9x + 18y + 6xy + 27


Here, we have a common factor 3 in all the terms.

∴    9x + 18y + 6xy + 27 = 3[3x + 6y + 2xy +9]

  We find that      3x + 6y = 3(x + 2y) and 2xy + 9 = 1(2xy+9)

i.e. a common factor in both the groups does not exist,

 Thus, 3x + 6y + 2xy + 9 cannot be factorised.

On regrouping the terms, we have

   3x + 6y + 2xy + 9 = 3x + 9 + 2xy + 6y
                            = 3(x + 3) + 2y(x + 3)
                            = (x + 3) (3 + 2y)

Now, 3[3x + 6y + 2xy + 9] = 3[(x + 3)(3 + 2y)]

Thus, 9x + 18y + 6xy + 27 = 3(x+3) (2y+3)

1245 Views

What is the common factor of 14x2y and 21xy2?

  • 7

  • xy

  • 7xy


C.

7xy

108 Views

What is the common factor of 2xy, 3pqr and 4lmn?

  • 0

  • 1

  • 12


B.

1

90 Views

What is the common factor of 2(x2y - xy2) and 8 (x4y2 - x2y4) ?

  • 2xy

  • 2x2y2

  • 2(x - y)


A.

2xy

88 Views

What is the common factor of p2q2, p2q2r2 and 3p2q2r2?

  • 3pqr

  • pq

  • p2q2


C.

p2q2

93 Views

Factors of 1 - x2

  • (1 - x) (1 - x)

  • (1 - x) (1 + x)

  • (1 + x) (1 + x)


B.

(1 - x) (1 + x)

92 Views