﻿ Factorise 9x + 18y + 6xy + 27 from Mathematics Factorisation Class 8 Manipur Board

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Factorise 9x + 18y + 6xy + 27

Here, we have a common factor 3 in all the terms.

∴    9x + 18y + 6xy + 27 = 3[3x + 6y + 2xy +9]

We find that      3x + 6y = 3(x + 2y) and 2xy + 9 = 1(2xy+9)

i.e. a common factor in both the groups does not exist,

Thus, 3x + 6y + 2xy + 9 cannot be factorised.

On regrouping the terms, we have

3x + 6y + 2xy + 9 = 3x + 9 + 2xy + 6y
= 3(x + 3) + 2y(x + 3)
= (x + 3) (3 + 2y)

Now, 3[3x + 6y + 2xy + 9] = 3[(x + 3)(3 + 2y)]

Thus, 9x + 18y + 6xy + 27 = 3(x+3) (2y+3)

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