Subject

Chemistry

Class

ICSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsLong Answer Type

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41.

(i)Calculate the solubility of AgCl in 0.2 M solution of sodium chloride. 

Ksp of AgCl = 1.2 x 10–10

(ii) A current of 10 A is passed for 80 min. and 27 seconds through a cell containing dilute sulphuric acid.

1.    How many moles of oxygen gas will be liberated at the anode ?

2.    Calculate the amount of zinc deposited at the cathode when another cell containing ZnSO4 solullon is connected in series (Zn = 65).

(iii) Calculate:

Ecell  at 25°C for the reaction

Zn + Cu2+ (0.20 M) → Zn2* (0.50M) + Cu

Given :

E° (Zn2+/Zn) = – 0.76 volt E°(Cu2+/Cu) = 0.34 volt


AgCl space equals space Ag to the power of plus space plus Cl to the power of minus
straight K subscript sp space equals space left square bracket Ag to the power of plus right square bracket left square bracket Cl to the power of minus right square bracket
left square bracket Ag to the power of plus right square bracket space equals space fraction numerator straight K subscript sp over denominator left square bracket Cl to the power of minus right square bracket end fraction

straight K subscript sp space equals space 1.2 space straight x space 10 to the power of negative 10 end exponent
conc. space NaCl space equals space left square bracket Na to the power of plus right square bracket space equals space 0.2 space straight M
left square bracket Ag to the power of plus right square bracket space equals fraction numerator 1.2 space straight x space 10 to the power of negative 10 end exponent over denominator 0.2 end fraction space equals space 6 space straight x space 10 to the power of negative 10 end exponent
therefore space solubility space of space AgCl space in space 0.2 space straight M space space solution space of space NaCl space space is space 6 space straight x space 10 to the power of negative 10 end exponent space mol space divided by straight L

ii right parenthesis space Following space reaction space take space place space during space electrolysis space of space straight H subscript 2 SO subscript 4
At space Cathode space 2 straight H to the power of plus left parenthesis aq. right parenthesis space plus 2 straight e to the power of minus space rightwards arrow space straight H subscript 2 left parenthesis straight g right parenthesis
At space space anode space straight H subscript 2 straight O space left parenthesis straight l right parenthesis space space rightwards arrow space 1 divided by 2 straight O subscript 2 left parenthesis straight g right parenthesis space space plus 2 straight H subscript 2 space left parenthesis straight g right parenthesis space space plus 2 straight e to the power of minus
straight W space equals straight E over 96500 space straight x space straight i space straight x space straight t
equals fraction numerator space 49 over denominator 96500 end fraction space straight x space 10 space straight x space left square bracket left parenthesis 80 space straight x space 60 right parenthesis plus 27 right square bracket
space equals space 5.07 space straight x space 10 to the power of negative 4 end exponent space straight x space 10 space straight x space 5
space equals space 25.70 space straight g
therefore space of space oxygen space liberated space at space anode space space equals space 25.70 space straight g
therefore space 32 space straight g space of space oxygen space equals space 1 space mole space of space oxygen space
25.70 space straight g space of space oxygen space space 1 over 32 space straight x space 25.70
space equals space 0.80 space moles space of space oxygen space
therefore space 0.8 space moles space of space oxygen space will space be space liberated space at space anode.

2 space colon space According space to space second space law space of space Faraday apostrophe straight s space electrolysis
fraction numerator weight space of space oxygen space libe over denominator weight space of space zince space deposited end fraction space equals space fraction numerator Eq. space wt. space of space straight a space oxygen over denominator Eq. space wt. space of space zinc end fraction

fraction numerator 25.70 over denominator wt. space of space zinc space deposited end fraction space equals space fraction numerator 16 over denominator 65 divided by 2 end fraction

wtl space of space zince space deposited space equals space fraction numerator 32.5 space straight x space 25.70 over denominator 16 end fraction
space equals space 52.2 space straight g


iii right parenthesis space In space the space given space cell space Zn space electrode space is space acting space as space anode space and space Cu space electrode space is space acting space as space cathode space.
straight E subscript cell superscript 0 space equals space straight E subscript straight c superscript 0 space minus straight E subscript straight A superscript 0
space equals space 0.34 minus left parenthesis negative 0.76 right parenthesis
equals space 0.34 space plus 0.76 space
equals 1.10 space straight V

straight E subscript cell superscript 0 space equals space straight E subscript cell superscript 0 space plus fraction numerator 0.059 over denominator 2 end fraction log space open square brackets Cu to the power of 2 plus end exponent over Zn to the power of 2 plus end exponent close square brackets
straight E subscript cell space equals space 1.1 plus 0.0295 space log space 0.4
equals 1.1 space plus 0.0295 space straight x space left parenthesis negative 0.397 right parenthesis
equals 1.1 minus 0.0117
equals 1.08 space straight V
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42.

Copper pyrites is an ore of copper.    

(i) Describe the process by which copper pyrites is concentrated.

(ii) Describe all the steps, with equations, to convert the concentrated ore to blister copper.

(iii) Describe the process of conversion of blister copper to pure copper.

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43.

(i) How is iodine manufactured from sea weeds ?   

(ii) How is hydrogen peroxide prepared in the laboratory ?

(iii) Give a balanced equation for a reaction in which hydrogen peroxide acts as a reducing agent and one in which it acts as an oxidizing agent.

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