Subject

Physics

Class

ICSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
Advertisement

 Multiple Choice QuestionsShort Answer Type

Advertisement

41. The following equation represents a fusion reaction :

straight H presubscript 1 presuperscript 2 space plus space straight H presubscript 1 presuperscript 3 space rightwards arrow space He presubscript 2 presuperscript 4 space plus space straight n presubscript 0 presuperscript 1 space plus space straight Q space semicolon

space where space straight Q space is space the space enrgy space released

Mass space of space straight H presubscript 1 presuperscript 2 space space atom space equals space 2.014102 space straight u

Mass space of space straight H presubscript 1 presuperscript 3 space atom space equals space 3.016050 space straight u

Mass space of space He presubscript 2 presuperscript 4 space atom space equals space 4.002603 space straight u

Mass space of space space neutron space space straight n presubscript 0 presuperscript 1 space equals space 1.008665 space straight u

Calculate the value of Q.


straight H presubscript 1 presuperscript 2 space plus space straight H presubscript 1 presuperscript 3 space rightwards arrow space He presubscript 2 presuperscript 4 space plus space straight n presubscript 0 presuperscript 1 space plus space straight Q space

Mass defect Δ m = Mass of reactant - Mass of product

equals space straight m space left parenthesis straight H presubscript 1 presuperscript 2 right parenthesis space plus space straight m left parenthesis straight H presubscript 1 presuperscript 3 right parenthesis space minus space open square brackets straight m open parentheses He presubscript 2 presuperscript 4 close parentheses space plus space straight n presubscript 0 presuperscript 1 space plus space straight Q close square brackets space

equals space left parenthesis 2.014102 space plus space 3.016050 right parenthesis space minus space left parenthesis 4.002603 space plus space 1.008665 right parenthesis

equals space 5.030152 minus 5.011268 space equals space 0.018884 space straight u

straight Q space equals space increment mc squared

space space space space equals space 0.018884 space straight x space 931 space MeV space
space
space space space space equals space 17.581004 space MeV space

space space space space equals space 17.581004 space straight x space 10 to the power of 6 space straight x space 1.6 space straight x space 10 to the power of negative 19 end exponent space straight J space space

space space space space equals space 28.13 space straight x space 10 to the power of negative 13 space end exponent

space space space equals space 2.81 space straight x space 10 to the power of negative 12 end exponent space straight J space
677 Views

Advertisement
42. What is a Zener diode? Explain how it can be used to stabilise the voltage in a circuit.
381 Views

43. The output of an OR gate is connected to the input of a NOT gate. Draw the logic circuit of this combination and write its truth table.  
203 Views

 Multiple Choice QuestionsLong Answer Type

44.

The current flowing through a conductor is given by I = neAvd

(i) Identify each term in the equation.

(ii) Obtain an expression for vd, if the current flowing through the conductor of length I has its ends maintained at a potential difference of V volts.

1460 Views

Advertisement
45.

(i) Write an expression for Biot-Savart’s law in the vector form. Write an expression for the magnetic field at the centre of a circular coil of radius R, with N turns and carrying a current I. 

(ii) A helium nucleus completes one round of a circle of radius 0.8 m in 2 seconds. Find the magnetic field at the centre of the circle.

278 Views

46. Show that straight I subscript rms space equals space fraction numerator straight I subscript straight o over denominator square root of 2 end fraction where Irms is the root mean square value of alternating current and I0 is its peak value.
359 Views

47.

(i) Derive an expression for the fringe width ‘y’ in Young’s double slit experiment. Use X as the wavelength of the monochromatic source, D as the distance of the screen from the slits and d as the distance of separation between the slits.

(ii) How does the fringe pattern change if the monochromatic source of light in the above experiment is replaced by a white source of light ?

4741 Views

Advertisement